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Alenkinab [10]
3 years ago
14

Understands how formulas are used​

Physics
2 answers:
Anna11 [10]3 years ago
5 0

Answer:

do it ur self i d k

Explanation:

Natali [406]3 years ago
4 0

Answer:

a map tell u sum to do

Explanation:

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How long does it take a 750-w coffeepot to bring to a boil 0.75 l of water initially at 11°c? assume that the part of the pot wh
Evgen [1.6K]
Just add all of them up and there is your answer I just added it but  I want u to work it out to..


4 0
3 years ago
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

T^2 \propto R^3

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

T^2 \propto R^3

T^2 = kR^3

Substituting the values, we get the value of constant k for mars.

687^2 = k\times (2.279 \times 10^{11})^3

k = 3.92 \times 10^{-29}

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

365^3 = 3.92\times 10^{-29} R^3

R^3 = 3.39 \times 10^{33}

R= 1.50 \times 10^{11}\;\rm m

Hence we can conclude that the distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

6 0
3 years ago
Flying against the wind, an airplane travels 2670 km in 3 hours. Flying with the wind, the same plane travels 11,070 km in 9 hou
xxMikexx [17]

Answer:

speed of plane in still air = 1060 km/h

speed of wind = 170 km/h

Explanation:

Let teh speed of plane in still air is vp and the speed of air is va.

Irt travels 2670 km in 3 hours against the wind

So,

vp - va = 2670 / 3 = 890 km/h ..... (1)

It travels 11070 km in 9 hours along the wind.

vp + va = 11070 / 9 = 1230 km/h .... (2)

Adding both the equations

2 vp = 2120

vp = 1060 km/h

and va = 1230 - vp = 1230 - 1060 = 170 km/h

5 0
3 years ago
If you have a mass of 50 kg on <br> Earth, what is your weight in Newtons?
Bond [772]
Weight on any planet is (mass) x (acceleration of gravity there).

Acceleration of gravity on Earth is about 9.8 meters per second² .
So weight of 50 kg on Earth is  (50 x 9.8) = <u>490 newtons</u>.

(That's about  110.2 pounds.)
5 0
3 years ago
Read 2 more answers
The same book is placed on a table .9m high. What type of energy does it have and how much?
Lina20 [59]

<em>mass (m)= 5 kg</em>

<em>height (h)= 9m </em>

<em>gravity (g)= 9.8 m/s^2</em>

It has Potential energy. (PE)

• PE = mgh

Replacing:

PE = 5 * 9.8 * 9 = 441 Joules

6 0
1 year ago
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