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aksik [14]
3 years ago
6

The atomic mass of gold is 197 g/mole, and the density of gold is 19.3 g/cm3. using this information along with the measured val

ue of young's modulus, calculate the speed of sound in gold.
Chemistry
1 answer:
olganol [36]3 years ago
6 0
The speed of sound is given by the formula
Speed of sound = square root (Young's Modulus/density)
Young's modulus for gold = 78 GPa which is 7.8 * 10^10 Pa
Speed of sound = (7.8 * 10^10 / 19.3 ) = sqrt (4.04 * 10^9 )
Speed of sound = 6.36 * 10^4 m/s <<<=== answer.
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How many milliliters of 0.200 m fecl3 are needed to react with an excess of na2s to produce 1.38 g of fe2s3 if the percent yield
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<span>Answer: 100 ml
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<span>Explanation:


1) Convert 1.38 g of Fe₂S₃ into number of moles, n


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ii) molar mass of </span><span>Fe₂S₃ =2 x 55.8 g/mol + 3 x 32.1 g/mol = 207.9 g/mol
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iii) n = 1.38 g / 207.9 g/mol = 0.00664 moles of <span>Fe₂S₃
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<span>2) Use the percent yield to calculate the theoretical amount:
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<span>65% = 0.65 = actual yield/ theoretical yield =>


</span>theoretical yield = actual yield / 0.65 = 0.00664 moles / 0.65 = 0.010 mol <span>Fe₂S₃</span><span>

3) Chemical equation:
</span>

<span> 3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)


4) Stoichiometrical mole ratios:
</span>

<span>3 mol Na₂S : 2 mol FeCl₃ : 1 mol Fe₂S₃ : 6 mol NaCl


5) Proportionality:


</span>2moles FeCl₃ / 1 mol Fe₂S₃ = x / 0.010 mol Fe₂S₃
<span>
=> x = 0.020 mol FeCl₃


6) convert 0.020 mol to volume
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<span>i) Molarity formula: M = n / V
</span>

<span>ii) V = n / M = 0.020 mol / 0.2 M = 0.1 liter = 100 ml
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