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aksik [14]
3 years ago
6

The atomic mass of gold is 197 g/mole, and the density of gold is 19.3 g/cm3. using this information along with the measured val

ue of young's modulus, calculate the speed of sound in gold.
Chemistry
1 answer:
olganol [36]3 years ago
6 0
The speed of sound is given by the formula
Speed of sound = square root (Young's Modulus/density)
Young's modulus for gold = 78 GPa which is 7.8 * 10^10 Pa
Speed of sound = (7.8 * 10^10 / 19.3 ) = sqrt (4.04 * 10^9 )
Speed of sound = 6.36 * 10^4 m/s <<<=== answer.
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If the concentration of the HCl used in your titration was 1.00 M and you used 23.68 mL to reach the endpoint, calculate the con
drek231 [11]

Answer: The concentration of the OH-, CB = 0.473 M.

Explanation:

The balanced equation of reaction is:

2HCl + Ca(OH)2 ===> CaCl2 + 2H2O

Using titration equation of formula

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2 (from the balanced equation of reaction)

NB is the number of mole of base = 1 (from the balanced equation of reaction)

CA is the concentration of acid = 1M

CB is the concentration of base = to be calculated

VA is the volume of acid = 23.65 ml

VB is the volume of base = 25mL

Substituting

1×23.65/CB×25 = 2/1

Therefore CB =1×23.65×1/25×2

CB = 0.473 M.

6 0
3 years ago
What is another common name for the lanthanoids on the periodic table?
RUDIKE [14]
Lanthanide Lanthanoid, also called Lanthanide
7 0
3 years ago
One isotope of Br has a half-life of 16.5 hours. How much of a 2.00 gram sample remains at the end of 1.00 day?
valina [46]

Answer:

half life=16.5hrs

sample=2g

total time=1day=24hrs

no. of half lives=total time/half life

no. of half lives=24hrs/16.5hrs=1.45approx1.5

sample left=1/2n=1/2[1.5]=0.707gapprox

Explanation:

4 0
3 years ago
When comparing the two chair conformations for a monosubstituted cyclohexane ring, which type of substituent shows the greatest
Aleksandr [31]

Answer:

See the explanation

Explanation:

In this case, we have to keep in mind that in the monosubstituted product we only have to replace 1 hydrogen with another group. In this case, we are going to use the methyl group CH_3.

In the axial position, we have a more steric hindrance because we have two hydrogens near to the CH_3 group. If we have <u>more steric hindrance</u> the molecule would be <u>more unstable</u>. In the equatorial positions, we don't <u>any interactions</u> because the CH_3 group is pointing out. If we don't have <u>any steric hindrance</u> the molecule will be <u>more stable</u>, that's why the molecule will <u>the equatorial position.</u>

See figure 1

I hope it helps!

6 0
3 years ago
what is the molarity of a solution that has 1.54 moles NaCI in a 3.7L solution. How do you prepare 50ml of 0.5 M of KCI from a s
dsp73

Answer:

69jtententemwntsj6e

Explanation:

uegehwhb3iejebb

8 0
3 years ago
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