If you mix equal concentrations of reactants and products, will the reaction proceed to the right or the left? HF(aq)+NO3−(aq)⇌H
1 answer:
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Lewis Structure is drawn in following steps,
1) Calculate Number of Valence Electrons:
# of Valence electrons in Mg = 2
# of Valence electrons in I = 7
# of Valence electrons in I = 7
---------
Total Valence electrons = 16
2) Draw Mg as a central atom surround it by two atoms of Iodine.
3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.
Total Valence electrons 16
- Four electrons - 4
----------
12
4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.
The final lewis structure formed is as follow,
1) Calculate Number of Valence Electrons:
# of Valence electrons in Mg = 2
# of Valence electrons in I = 7
# of Valence electrons in I = 7
---------
Total Valence electrons = 16
2) Draw Mg as a central atom surround it by two atoms of Iodine.
3) Connect each Iodine atom to Mg, and subtract two electrons per bond. In this case we will subtract 4 electrons from total valence electrons. i.e.
Total Valence electrons 16
- Four electrons - 4
----------
12
4) Now start adding the remaining 12 electrons on more electronegative atoms i.e. Iodine.
The final lewis structure formed is as follow,
Answer : The mass of copper deposit is, 1.98 grams
Explanation :
First we have to calculate the charge.
Formula used :
where,
Q = charge = ?
I = current = 10 A
t = time = 10 min = 600 sec (1 min = 60 sec)
Now put all the given values in this formula, we get
Now we have to calculate the number of atoms deposited.
As, 1 atom require charge to deposited =
Number of atoms deposited = atoms
Now we have to calculate the number of moles deposited.
Number of moles deposited = moles
Now we have to calculate the mass of copper deposited.
1 mole of Copper has mass = 63.5 g
Mass of Copper Deposited =
Therefore, the mass of copper deposit is, 1.98 grams