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3 years ago

How many protons, electrons, and neutrons does the following isotope contain? ^{18} \text{F}^{-} 18 F −

1 answer:

8 0

Isotope ¹⁸F⁻ contains:
1) p⁺ = 9; number of protons.
Fluorine has atomic number Z = 9 (total number of protons).
2) e⁻ = 10; number of electrons.
In element number of electrons and protons are the same, because element has neutral charge, but because in this example, fluorine is anion with negative charge, it has one electron more.
3) n° = 9; number of neutrons.
Mass number A = 18 is total number of protons and neutrons in a nucleus, so number of neutrons is A-Z = 18-9=9.

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The concentration of the hydronium ion in hydrochloric acid is 0.0045 M, and the pH of the solution is 2.34.

pH is the potential of the hydrogen or the hydronium ions in the aqueous solution.

As the solution contains $4.5 \times 10^{-3} \;\rm M\;$ HCl the concentration of the hydronium ion will be the same, $4.5 \times 10^{-3} \;\rm M.$

The pH of the solution is calculated as:

$\begin{aligned} \rm pH &= \rm -log[H^{+}]\\\\&= - \rm log (4.5 \times 10^{-3})\\\\&= 2.34\end{aligned}$

The concentration of the hydroxide ion is calculated from pH and hydronium ion as:

$\begin{aligned} \rm [H_{3}O^{+}][OH^{-}] &= 10^{-14}\\\\&= \dfrac{1 \times 10^{-14}}{4.5 \times 10^{-3}}\\\\&= 2.2 \times 10^{12}\end{aligned}$

Now, for the calcium hydroxide solution, the calculations are shown as,

$\begin{aligned} \rm (H_3}\rm O^{+}) &= \rm antilog (-pH)\\\\&= \rm antilog (-8)\\\\&= 10^{-8} \;\rm M\end{aligned}$

pOH is calculated as:

$\begin{aligned} \rm pOH &= 14- 8 = 6\\\\\rm [OH^{-}] &= \rm antilog (-6)\\\\&= 10^{-6} \end{aligned}$

The concentration of calcium hydroxide is calculated as:

$\begin{aligned} &= \dfrac{1}{2} \times \rm [OH^{-}]\\\\&= 5 \times 10^{-4} \;\rm M\end{aligned}$

Therefore, the pH and the pOH give the concentration of the hydrogen or the hydronium ion and the hydroxide ion.

Learn more about pH and pOH here:

brainly.com/question/16062632

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