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marysya [2.9K]
3 years ago
8

What is the ionic bonding of NaCl

Chemistry
1 answer:
madam [21]3 years ago
8 0
Na has a one proton over than electrons.so Na makes a Na+
Cl has a one electron overthan protons.so Cl makes a Cl-

proton has a + affectation
electron has a - affectation ..

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The diagram below represents the organizational levels of living things.
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Answer: its vein

Explanation:

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The radioactive decay of carbon-14 is first-order and the half-life is 5800 years. While a plant or animal is living, it has a c
Anestetic [448]
If the half life is 5800 years, and there was only 1/4 of the Carbon 14 left in the wood remains, then 1/2 of the 1/2 life or 1/4 is 2900 years so the total age of the wood should be 5800  + 2900 = 8700 years old. We found some ancient highly compressed and water logged wood branches in an old glacial lake in the Highland Valley of BC., Canada and the lake deposits were up to 40,000 yrs old or just past the limit of Carbon 14 dating. 
6 0
3 years ago
Someone please help will mark as brainliest
Bas_tet [7]

Answer:

4. A subscript is a sentence below a line. You cannot change subscripts in a chemical formula to balance a chemical equation

5. where's/whats the equation??

6. ^^^

Explanation:

7 0
3 years ago
How many grams of O2 are present in 44.1 L of O2 at STP?
ycow [4]

Taking into accoun the STP conditions and the ideal gas law, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

First of all, the STP conditions refer to the standard temperature and pressure, where the values ​​used are: pressure at 1 atmosphere and temperature at 0°C. These values ​​are reference values ​​for gases.

On the other side, the pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature.
  • R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.
  • n is the number of moles of the gas.

Then, in this case:

  • P= 1 atm
  • V= 44.1 L
  • n= ?
  • R= 0.082 \frac{atmL}{molK}
  • T= 0°C =273 K

Replacing in the expression for the ideal gas law:

1 atm× 44.1 L= n× 0.082 \frac{atmL}{molK}× 273 K

Solving:

n=\frac{1 atm x44.1 L}{0.082\frac{atmL}{molK}x273K}

n=1.97 moles

Being the molar mass of O₂, that is, the mass of one mole of the compound, 32 g/mole, the amount of mass that 1.97 moles contains can be calculated as:

1.97 molesx\frac{32 g}{1 mole}= 63.04 g ≈ <u><em>63 g</em></u>

Finally, the correct answer is option e. 63 grams of O₂ are present in 44.1 L of O2 at STP.

Learn more about the ideal gas law:

  • <u>brainly.com/question/4147359?referrer=searchResults</u>
7 0
3 years ago
Mixed Practice:
Afina-wow [57]

Given

Mass of NO - 824 g

Molar mass of NO - 30.01g/mol

No of moles of NO = Given mass/Molar mass

No of moles of NO = 824/30.01= 27.45 mole

Hence 27.5 moles of NO are formed!

5 0
3 years ago
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