The cofficent is 2 for diphosphorus trioxide
Coordination numbers are defined for the crystalline structures that tell about the numbers of atoms bonded to the central atom. The coordination number of a diamond is 4.
<h3>What is a coordination number?</h3>
A coordination number has been defining the number of the ions, atoms, and molecules that are bonded to the central atom of the crystalline compound or a complex.
The diamond has 8 carbon atoms in its one unit and its coordination number is 4 as its lattice type is face-centered cubic that has carbons at the corners and face center of the structure. One carbon contributes 1/8 hence and the faces center contributes 1/2.
Therefore, the diamond has a coordination number of 4.
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Answer: A is condensation and B is freezing.
The process in which the gas changes to the liquid phase due to the removal of heat is known as condensation. Rains are formed in this way. The water vapour rises. As it raises above it loses heat and then cools down and condenses and comes down as rainfall.
The process in which the liquid changes to a solid on removal of heat is known as freezing. Formation of ice is an example. When the heat is removed at -4 degree Celsius the water freezes to ice.
I will try my best to sovle this question...
Im Pretty sure it has to be A. it needs to balance it would not stand in place if not balanced.
Answer: Volume occupied by given neon sample at standard condition is 123.84 L.
Explanation:
Given:
= 105 L,
,
= 985 torr
At standard conditions,
= 273 K,
= 760 K,
= ?
Formula used to calculate the volume is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that volume occupied by given neon sample at standard condition is 123.84 L.