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Maurinko [17]
3 years ago
6

When there are too many neutrons compared to the number of protons, the atomic nucleus is

Physics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

99.9% sure it B. Unstable but if that’s wrong try A.stable

Explanation:

Too many protons (or too few neutrons) in the nucleus result in an imbalance between forces, which leads to nuclear instability.

if a nucleus is unstable due to too many neutrons, it will undergo Beta decay - this means they become stable by emitting a beta particle.

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In which direction does gravitational force act
Sunny_sXe [5.5K]
Gravitational force pushes down on us to keep us on the ground. So it pushes in a downward direction.
4 0
3 years ago
A girl walked 200 m from her home to her friend’s home, then she walked 1 km to a shop. She then walked 800 m back to her home.
timama [110]

Answer:

200 meters+1000 meters+800 meters=2000 meters or 2km

Explanation:

1km=1000m

3 0
3 years ago
How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
Which two particles would be attracted to each other?
balandron [24]
U need a positive and a negative i will say b cause electron r negative and protons are positive 
8 0
3 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Svet_ta [14]

Answer:

The speed is \sqrt{2}v_{0}.

(a) is correct option.

Explanation:

Given that,

Potential difference V= V_{0}

Speed v = v_{o}

If it were accelerated instead

Potential difference V'=2V_{0}

We need to calculate the speed

Using formula of initial work done on proton

W = q V

We know that,

\Delta W=\Delta K.E

q V=\dfrac{1}{2}mv^2

Put the value into the formula

q V_{0}=\dfrac{1}{2}mv_{0}^2

v_{0}^2=\dfrac{2qV_{0}}{m}....(I)

If it were accelerated instead through a potential difference of 2 V_{0}, then it would gain a speed will be given as :

Using an above formula,

v_{0}'^2=\dfrac{2qV_{0}}{m}

Put the value of V_{0}

v_{0}'^2=\dfrac{2q\times2V_{0}}{m}

v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}

v_{0}'=\sqrt{2}v_{0}

Hence, The speed is \sqrt{2}v_{0}.

6 0
3 years ago
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