Answer: 11 year
P(1) = 37,100
P(4) = 58,400
The linear equation (for x ≥ 1)
P(x) = 37,100 + a(x-1)
For x = 4
58,400 = 37,100 + a(4-1)
58,400 - 37,100 = 3a
21300 = 3a
a = 7100
So, the linear equation:
P(x) = 37100 + 7100*(x-1)
P(x) = 37100 + 7100x - 7,100
P(x) = 7100x + 30000
To find when the profit should reach 108100, we can substitute P(x) by 108100.
108100 = 7100x + 30000
108100 - 30000 = 7100x
78100 = 7100x
x = 78100/7100
x = 11
Answer: 11 year
Answer:
Hi,can you please answer mine too it's question 9-12 I really need the answer because I have to pass it tomorrow morning:(
Step-by-step explanation:
about your question I'll put it in the comment section:)
Step 1. Simplify 9^2 to 81
81 <span>÷ (-3)^0
Step 2. Use Rule of Zero: x^0 = 1
81 </span><span>÷ 1
Step 3. Simplify
81</span>
Answer:
do you still need this answer to this question and where is the other question??
Step-by-step explanation:
The soultion for the set is the second one
