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3 years ago

3. A stone is thrown upward at an angle. What happens to the horizontal component of its velocity as it rises

Physics

1 answer:

Dominik [7]3 years ago

3 0

Answer:

The horizontal component of the velocity does not change.

Explanation:

Neglecting air resistance, there is no other force acting against the horizontal component, and hence the velocity does not change.

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Which of these could NOT be used to find the mechanical advantage of an inclined plane?

34kurt

The "c) percent efficiency" could not be used to find the mechanical advantage of an inclined plane. There are two formulae that could be used to determine the mechanical advantage of an inclined plane which stated as MA = Length/rise and Wout=Win. MA is the mechanical advantage, Wout is the output force, Win is the input force, and "rise" is the height of the inclined plane<span>.</span>

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3 years ago

An eagle flying at 35 m/s emits a cry whose frequency is 440 Hz. A blackbird is moving in the same direction as the eagle at 10

Akimi4 [234]

Answer:

a) $F=475.7Hz$

b) $F'=410.899Hz$

Explanation:

From the question we are told that:

Velocity of eagle $V_1=35m/s$

Frequency of eagle $F_1=440Hz$

Velocity of Black bird $V_2=10m/s$

Speed of sound $s=343m/s$

Generally the equation for Frequency is mathematically given by

$F=f_0(\frac{v-v_2}{v-v_1})$

$F=440(\frac{343-10}{343-35})$

$F=475.7Hz$

Generally the equation for Frequency is mathematically given by

$F'=f_0(\frac{v+v_2}{v+v_1})$

$F'=440(\frac{343+10}{343+35})$

$F'=410.899Hz$

7 0

3 years ago

Which of the following will cause a decrease in an object's weight? Increase in the mass of the object Decrease in the mass of t

Paul [167]

A decrease in mass will decrease an objects weight because
weight = mass x gravitational constant

4 0

3 years ago

Read 2 more answers

a 45 kg ice skater initially skating at a velocity of 3 m/s speeds up to a velocity of 5 m/s. calculate the difference in the ma

ad-work [718]

Answer: 90 kgm/s

Explanation:

The momentum (linear momentum) $p$ is given by the following equation:

$p=m.V$

Where:

$m=45 kg$ is the mass of the skater

$V$ is the velocity

In this situation the skater has two values of momentum:

Initial momentum: $p_{1}=m.V_{1}$

Final momentum: $p_{2}=m.V_{2}$

Where:

$V_{1}=3 m/s$

$V_{1}=5 m/s$

So, if we want to calculate the difference in the magnitude of the skater's momentum, we have to write the following equation(assuming the mass of the skater remains constant):

$p=p_{2}-p_{1}=m.V_{2}-m.V_{1}$