Answer:
(a) The magnitude of the applied force is (0.0001524k) Newton
(b) Corresponding stress in the steel core = (0.0001524k/area) Newton per meter square
Explanation:
(a) From Hookes law of elasticity,
Force applied = force constant (k) × compression
compression = 0.006 in = 0.006 × 0.0254 = 0.0001524 meter
Force applied = k × 0.0001524 = (0.0001524k) Newton
(b) Stress = Force applied (Newton)/area of steel core (meter square) = (0.0001524k/area) Newton per meter square
1 astronomical unit 1 AU = 1.4960 * 10^11 meters
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
= 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11 AU
= 3.0.74 / 100 = 0.0374 AU
Answer:
24volts
Explanation:
If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;
Q = CV where;
Q is the charge flowing across the capacitor
C is the capacitance of the capacitor. = 15-µF
V is the voltage = 40V
Q = 15×10^-6×40
Q = 0.0006coulombs
If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;
Q = CV
V = Q/C
V = 0.0006/25×10^-6
V = 24Volts
Therefore, the final potential difference across the 25-µF capacitor will be 24volts
Explanation:
Work done = F * d = 100N * 0.5m = 50J.
No it does not because this weight is being balanced by a normal source
