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3 years ago

How are musical instruments grouped?

Physics

2 answers:

vovikov84 [41]3 years ago

7 0

Musical instruments are grouped by how they produce the pitch.

Pitch is the highness or lowness of a tone.

rosijanka [135]3 years ago

6 0

A and B are equivalent. That's one way instruments are often grouped. (the "sopranos", the "altos", the "bass")

C is another way instruments are often grouped; (the "woods", the "brass")

D is another way instruments are often grouped; (the "strings", the "percussions")

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A 70kg car drives through a curve with radius 50m. What is the minimum angle the road should be tilted to keep the car on the ro

worty [1.4K]

when car moves along a circular path then centripetal force for taking turn will be provided by the component of normal force

Let the road is tilted by some angle

so force equations are given as

$F_n cos\theta = mg$

$F_n sin\theta = \frac{mv^2}{R}$

now divide two equations

$tan\theta = \frac{v^2}{Rg}$

now as it is given to us that

$v = 80 km/h$

$v = 80* \frac{5}{18} = 22.2 m/s$

$R = 50 m$

now we have

$tan\theta = \frac{22.2^2}{50*9.8}$

$tan\theta = 1$

$\theta = tan^{-1}1$

$\theta = 45^0$

so it is inclined at an angle of 45 degree

8 0

3 years ago

Three deer, a, b, and c, are grazing in a field. deer b is located 62.1 m from deer a at an angle of 54.3 ° north of west. deer

sveticcg [70]

by cosine law we know that

$c^2 = a^2 + b^2 - 2 abcos\theta$

$\theta = 180 - 54.3 - 79.1 = 46.6 degree$

now using above equation

$93.8^2 = 62.1^2 + b^2 - 2*62.1*b * cos46.6$

$4942.03 = b^2 - 85.34 b$

$b^2 - 85.34b - 4942.03 = 0$

by solving above quadratic equation we have

$b = 124.9 m$

so it is at distance 124.9 m from deer a

4 0

3 years ago

Will give correct answer brainliest please help

ikadub [295]

Answer:

it is the 3rd answer choice

6 0

3 years ago

A typical flying insect applies an average force equal to twice its weight during each downward stroke while hovering. Take the

Lelu [443]

Answer:

Average power output of insect is 2.42W

Explanation:

Workdone by constant force during displacement is given by:

W= F× d cos theta

Where theta is angle between F and d.

Power output due to the force over the interval time is given by:

P= Workdone/change in time

Ginen:

Mass of insect,m= 7.0g= 7/1000 = 0.07kg

Downward force applied by insect,F= 2mg

Distance moved by the wing each stroke=1.5cm=1.5/100= 0.015m

W= F× d cos theta

Where theta=0° since force is in the same direction as the displacement.

W= 2mg×d

W= 2× 0.07 × 9.8 × 0.015

W= 0.02058J

Power output = W/ change in time

Since wings make 117strokes each second time interval is 1/117 = 8.5×10^-3seconds

Power= 0.02058/(8.5×10^-3)

Power= 2.42W

6 0

3 years ago

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers.

AVprozaik [17]

Answer:

F = 1.63 x 10⁻⁹ N

Explanation:

Complete question is as follows:

The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?

Answer:

The gravitational force is given by Newton's Gravitational Law as follows:

F = Gm₁m₂/r²

where,

F = Gravitational Force = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of each ball = 7 kg

r = distance between balls = 2 m

Therefore,

F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²

7 0

3 years ago