What is the mass of silver that can be prepared from 2.10 g of copper metal? Cu(s)+2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)

2 answers:

7 0

Moles of Cu = 2.10 /21 = 0.1 Moles of Ag produced is 0.2 Mass of Ag = 0.2 x 108 = 21.6 g. 0.500 g/108 = 0.046 moles, but Cu. moles produced will be half as much, from equation = 0.23moles mass of Cu = 0.023 x2.10 = 0.0483g

VLD [36.1K]3 years ago

3 0

The mass of silver that can be prepared from 2.10 g of copper metal are 7.128 grams of Ag

calculation

Cu(s) + 2AgNO3 (aq) → Cu(NO3)2 +2 Ag (s)

find the moles of Cu

= mass/ molar mass

= 2.10 g / 63.5 g/mol = 0.033 moles

Use the mole ratio to determine the moles of Ag

The mole ratio of Cu : Ag is 1:2 therefore the moles of Ag = 0.033 x2=0.066 moles

mass of Ag = moles x molar mass

= 0.066 moles x 108 g/mol = 7.128 grams of Ag

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In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.

olga nikolaevna [1]

Answer:

a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

$A=\pi ^{1/3} (6V)^{2/3}$