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ladessa [460]
3 years ago
15

What is the mass of silver that can be prepared from 2.10 g of copper metal? Cu(s)+2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)

Chemistry
2 answers:
zhenek [66]3 years ago
7 0
<span>Moles of Cu = 2.10 /21 = 0.1 Moles of Ag produced is 0.2 Mass of Ag = 0.2 x 108 = 21.6 g. 0.500 g/108 = 0.046 moles, but Cu. moles produced will be half as much, from equation = 0.23moles mass of Cu = 0.023 x2.10 = 0.0483g</span>
VLD [36.1K]3 years ago
3 0

 The mass  of silver that can be prepared from 2.10 g of copper  metal are  7.128  grams  of Ag


 <u><em>calculation</em></u>

 Cu(s)  + 2AgNO3 (aq)  →  Cu(NO3)2  +2 Ag (s)

  find the moles of Cu

 = mass/ molar mass

= 2.10 g / 63.5 g/mol = 0.033  moles


Use the mole  ratio to determine  the  moles of Ag

The mole ratio of Cu : Ag is  1:2 therefore the moles of Ag = 0.033 x2=0.066 moles


mass of Ag =  moles x molar  mass

= 0.066 moles x  108   g/mol  = 7.128   grams of Ag

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