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larisa [96]
3 years ago
6

An unknown substance was observed to have the following properties: colorless liquid that feels slippery, pH of 8.5, turns red l

itmus to blue. Based on these properties, what is the best classification of this substance?
acid


base


element


salt
Physics
2 answers:
natka813 [3]3 years ago
5 0

Answer:it’s a base

Explanation: this is because the bases have a very bitter taste but a very slippery feel at the same time leading to a substance with a ph of 8.5 and the red turning to blue so this is a base

Mashcka [7]3 years ago
3 0

Answer:

It is a base

Explanation:

Because

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Auniform thin film of n=1.33 is on top of glass (n=1.5). When monochromatic light with tunable wavelength is directed from above
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Answer:

Explanation:

There is reflection ( two times ) from upper and lower surface of the film . In both cases , reflection is from low to  high density medium so there is change in phase of 180 twice .

So for constructive interference

2μd = n λ₁ , d is thickness required , λ is wavelength n₁ is order of  bright fringe

For destructive interference ( minimum light )

2μd = (2n+1) λ₂/2

n λ₁ =(2n+1) λ₂/2

(2n+1) / 2n = λ₁ / λ₂

= 650 / 505

=   5 / 4 ( approx )

2n = 4

n = 2

2μd = n λ₁

2 x 1.33 x d = 2 x 650 nm

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How would the mathematical model change if the direction that the object traveled was reversed
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A line that is falling towards the x axis represents an object that is negatively accelerating, or slowing down. When the line hits the x axis, the object has stopped moving. If the graph continues below the x axis, the object has changed direction and is moving backwards at increasing velocity.
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Mia wanted to know how Earth’s movements created new landforms. She decided to read about folded mountains and their characteris
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What obstacles will you need to deal with to build railroad routes
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<u>Answer:</u>

<em>Construction of a railroad route is a strenuous task and one has to face several obstacles. </em>

<u>Explanation:</u>

Setting up the best possible plan for laying a rail route is a time-taking task. Several factors like economical nature of the plan, proper availability of building materials, minimum river crossings etc should be considered.

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4 0
3 years ago
A rock is thrown upward from the top of a 30 m building with a velocity of 5 m/s. Determine its velocity (a) When it falls back
Kobotan [32]

Answer:

a) 5 m/s

b) 17.8542 m/s

c) 24.7212 m/s

0.229

Explanation:

t = Time taken

u = Initial velocity = 5 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=5-9.81\times t\\\Rightarrow \frac{-5}{-9.81}=t\\\Rightarrow t=0.51 \s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=5\times 0.51+\frac{1}{2}\times -9.81\times 0.51^2\\\Rightarrow s=1.27\ m

So, the stone would travel 1.27 m up

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.27+0^2}\\\Rightarrow v=5\ m/s

Velocity as the rock passes through the original point is 5 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 1.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.27\times 2}{9.81}}\\\Rightarrow t=0.51\ s

Time taken to reach the original point is 0.51+0.51 = 1.02 seconds

So, total height of the rock would fall is 30+1.27 = 31.27 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 16.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{16.27\times 2}{9.81}}\\\Rightarrow t=1.82\ s

Time taken by the stone to reach 15 m above the ground is 1.82+0.51 = 2.33 seconds

v=u+at\\\Rightarrow v=0+9.81\times 1.82\\\Rightarrow v=17.8542\ m/s

Speed of the ball at 15 m above the ground is 17.8542 m/s

s=ut+\frac{1}{2}at^2\\\Rightarrow 31.27=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{31.27\times 2}{9.81}}\\\Rightarrow t=2.52\ s

v=u+at\\\Rightarrow v=0+9.81\times 2.52\\\Rightarrow v=24.7212\ m/s

Speed of the stone just before it hits the street is 24.7212 m/s

F = Force

m = Mass = 100 kg

g = Acceleration due to gravity = 9.81 m/s²

s = Displacement = 4 km = 4000 m

P = Power = 1 hp = 745.7 Watt

t = Time taken = 20 minutes = 1200 seconds

μ = Coefficient of sliding friction

F = μ×m×g

⇒F = μ×100×9.81

W = Work done = F×s

P = Work done / Time

⇒P = F×s / t

745.7=\frac{\mu \times 981\times 4000}{1200}\\\Rightarrow \mu=\frac{747.5\times 1200}{981\times 4000}\\\Rightarrow \mu=0.229

Coefficient of sliding friction is 0.229

8 0
3 years ago
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