11. D
12.C
13. For 13 i would say B but not so sure
14. A
We can use the formula P=IV to calculate the current, where “P” is power (measured in watts), “I” is current (measured in Amps), and “V” is voltage. Simply plug and solve:
P = IV
(3.5 Watts) = I(120 volts)
I = 0.0292 Amps
The current flowing through the bulb is approximately 0.0292 Amps.
Hope this helps!
NH4NO3 b) C8H8O4 c) O3 d) C3H5(NO3)3
Answer:
Hi.. U should do like this
Cu + S - - - >Cu2S
