Yes it can cause chemical change
Answer : The value of
for
is
.
Solution : Given,
Solubility of
in water = 
The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.
The equilibrium equation is,

Initially - 0 0
At equilibrium - s s
The Solubility product will be equal to,
![K_{sp}=[Ba^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BBa%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)

![[Ba^{2+}]=[CO^{2-}_3]=s=4.4\times 10^{-5}mole/L](https://tex.z-dn.net/?f=%5BBa%5E%7B2%2B%7D%5D%3D%5BCO%5E%7B2-%7D_3%5D%3Ds%3D4.4%5Ctimes%2010%5E%7B-5%7Dmole%2FL)
Now put all the given values in this expression, we get the value of solubility constant.

Therefore, the value of
for
is
.
Answer:
NH3 is polar due to the bonds between nitrogen and hydrogen which have different electronegativity and due also to its asymmetrical shape.
Explanation:
NH3 is polar as there are 3 dipoles in the ammonia molecule that do not balance each other out.
Considering the N-H bond which is polar because N with an electronegativy of 3.0, is more electronegative than H, with an electronegativity of 2.1. The is overall asymmetrical shape of NH3
means that the dipoles remains unbalanced and do cancel out each other making the NH3 polar.
Answer:
(S)-3-methoxy-3-methylbutan-2-ol
Explanation:
In this case, we have an <u>epoxide opening in acid medium</u>. The first step then is the <u>protonation of the oxygen</u>. Then the epoxide is broken to generate the most <u>stable carbocation</u>. The nucleophile (
) will attack the carbocation generating a new bond. Finally, the oxygen is <u>deprotonated</u> to obtain an ether functional group and we will obtain the molecule <u>(S)-3-methoxy-3-methylbutan-2-ol</u>.
See figure 1
I hope it helps!
Answer:
moles = given mass/atomic mass
so H2O mass = 2 +16=18
so 12g of h2o= 12/16 = 3/4 moles