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Aneli [31]
3 years ago
9

A small metal cube measures 2.5 cm on one side. The mass of the cube is 1129.56 g. What is the density of the cube?

Physics
1 answer:
attashe74 [19]3 years ago
8 0

-- volume = (length)(width)(height)

-- Since the cube is a cube, its three dimensions are all the same number.

Volume = (2.5cm)(2.5cm)(2.5cm)

Volume = 15.625 cubic cm

-- density = (mass) / (volume)

Density = (1129.56g) / (15.625cm^3)

Density = 72.3 g/cm^3

(roughly 3.2 TIMES the density of the most dense naturally occurring substance on Earth)

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oksian1 [2.3K]

Answer:

Yes

Explanation:

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3 years ago
A 2kg hockey puck is sliding across the ice skating rink at 2 m/s. A player hits the puck so it's velocity increases to 10 m/s.
konstantin123 [22]

The work done on the puck is 96 J

Explanation:

According to the work-energy theorem, the work done on the hockey puck is equal to the change in kinetic energy of the puck.

Mathematically:

W=K_f -K_i= \frac{1}{2}mv^2-\frac{1}{2}mu^2

where

K_f = \frac{1}{2}mv^2 is the final kinetic energy of the puck, with

m = 2 kg being the mass of the puck

v = 10 m/s is the final speed

K_i = \frac{1}{2}mu^2 is the initial kinetic energy of the puck, with

u = 2 m/s being the initial speed of the puck

Substituting numbers into the equation, we find the work done by the player on the puck:

W=\frac{1}{2}(2)(10)^2 - \frac{1}{2}(2)(2)^2=96 J

Learn more about work and kinetic energy:

brainly.com/question/6763771  

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brainly.com/question/6536722

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6 0
3 years ago
The leaning tower of Pisa is about 56 meters tall. A ball released from the top takes 3.4 seconds to reach the ground. The final
geniusboy [140]
S=56, u=0, v=33, a=?, t=3.4

v=u+at
33=3.4 a
a = 9.7m/s^2
7 0
3 years ago
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Snowcat [4.5K]

Explanation:

The wavelength of green light is about 500 nanometers, or two thousandths of a millimeter. The typical wavelength of a microwave oven is about 12 centimeters, which is larger than a baseball.

5 0
3 years ago
Two conducting spheres are each given a charge Q. The radius of the larger sphere is three times greater than that of the smalle
padilas [110]

Answer:

Explanation:

If E₀ is the electric field outside the smaller sphere and r is the radius of larger sphere.

E₀ = kQ/r²

The radius of the larger sphere is 3r and the charge on both sphere is same then the electric field outside the larger sphere is given as

E = kQ/(3r)² = kQ/9r² = 1/9 (kQ/r²)= 1/9 x E₀

hence the correct option is e.

5 0
3 years ago
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