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3 years ago

Elements in group via (group 16) have similar properties because they all have __________.

Chemistry

2 answers:

Ksivusya [100]3 years ago

6 0

They all have 2 elections in the outer S orbital, and 4 electrons in the P orbitals.

RUDIKE [14]3 years ago

4 0

Explanation:

Chemical properties are defined as the properties which tend to show change in chemical composition of a substance.

For example, toxicity, reactivity, combustion etc are all chemical properties.

It is known that elements which belong to same period show similar chemical properties.

This is because elements that lie in the same group have same number of valence electrons. Hence, they tend to show same type of reactivity which makes them exhibit similar chemical properties.

Thus, we can conclude that elements in group via (group 16) have similar properties because they all have 6 valence electrons.

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The atomic mass is equal to what?

dsp73

Answer:

The mass number

Explanation:

I hope this helps.

4 0

3 years ago

Read 2 more answers

Question 2 of 50

wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

Write the balanced chemical equation for the given reaction.
Convert the mass of calcium carbonate into moles.
Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

$CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}$

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

$mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}$

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

$mol \ CaO \ = 0.2498 \ mol$

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

$mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g$

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

$\boxed {mass \ CaO \ = 14 \ g}$

Learn More

Learn more about stoichiometry brainly.com/question/12979299
Learn more about mole conversion brainly.com/question/12972204
Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0

3 years ago

What is the temperature difference if 300 cal are used to warm water

PIT_PIT [208]

Answer:

The temperature difference is $\frac{300}{m} Kkg^{-1}$

Explanation:

The formula that is to used is :

Δ $Q=ms$ Δ $T$

where ,

Δ $Q$ is the heat supplied in calories = 300cal
$m$ is the mass of water taken = m (assumed)
Δ $T$ is the change in temperature
$s$ is the specific heat of water = $1calK^{-1}Kg^{-1}$

ΔT :

$\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}$

6 0

3 years ago

Earth is approximately 1.5 x 10^8 km from the sun the. How far is earth from the sun meters

Zielflug [23.3K]

Answer:

${ \tt{1 \: km = 1000m}} \\ { \tt{1.5 \times {10}^{8} km = (\frac{1.5 \times {10}^{8} \times 1000 }{1} )m}} \\ = 1.5 \times {10}^{11} \: metres$

4 0

2 years ago

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

user100 [1]

Answer:

c 43.38 g

Explanation:

The reaction between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.

For the fact that HCl gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess, while the limiting reagent should be MnO2 .

Thus, the theoretical yield of Cl2 will be 60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% * 60.25 = 43.38 g

5 0

3 years ago