When you flick on a light with a regular incandescent bulb, electricity is converted to heat in the tiny, tungsten wire inside. In a 75-watt bulb, the wire heats up to about 4600 degrees Fahrenheit! At such a high temperature, the energy radiating from the wire includes some visible light. Incandescent light bulbs aren’t the most efficient light source, though, because 90% of the electricity they use produces heat, while a measly 10% produces light.
Fluorescent bulbs are designed to produce light without so much heat. Forty percent of the electricity they use produces light, which might not sound so impressive unless you compare it with incandescents.
When you turn on a fluorescent light, electrons collide with mercury atoms inside the bulb, producing ultraviolet light. We can’t see ultraviolet light, so there’s a thin layer of phosphor powder inside the bulb to convert the ultraviolet to visible light. Fluorescent bulbs stay cooler because this process produces much less heat to begin with, and because their bigger size helps disperse heat more quickly.
What do these heated differences mean for energy efficiency? A regular incandescent light bulb uses about four times as much energy as a fluorescent bulb, to produce the same amount of light.
Answer:
2 K(s) + Cl₂(g) ⟶ 2 KCl(s)
2 Cu(s) + O₂(g) ⟶ 2 CuO(s)
Explanation:
Both reactions are synthesis reactions (two substances combine to form another).
Reaction: K(s) + Cl₂(g) ⟶
The product is the binary salt KCl. The balanced chemical equation is:
2 K(s) + Cl₂(g) ⟶ 2 KCl(s)
Reaction: Cu(s) + O₂(g) ⟶
The most likely product is the metal oxide CuO. The balanced chemical equation is:
2 Cu(s) + O₂(g) ⟶ 2 CuO(s)
Answer:
maybe 1 or 3 im not sure
Explanation:
i didn't study it yet sorry for not helping but try asking someone else
Answer:
2.67 M
Explanation:
Molarity, which is the molar concentration of a substance, can be calculated using the formula;
M = n/V
Where;
M = molarity (M)
n = number of moles (mol)
V = volume (Litres)
Based on the provided information in this question, mass of lithium sulfate (Li2SO4) = 734g, volume = 2.5L
Using mole = mass/molar mass
Molar mass of Li2SO4 = 7(2) + 32 + 16(4)
= 14 + 32 + 64
= 110g/mol
Mole = 734/110
Mole (n) = 6.67moles
Molarity = n/V
Molarity = 6.67/2.5
Molarity = 2.668
Molarity of Li2SO4 in the solution is 2.67 M
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is 
Explanation:
From the question we are told that
The voltage of the cell is 
Generally 
is mathematically represented as
Where 
is the equilibrium constant for this auto-ionization of water with a value 
Generally the 
is mathematically represented as
=> 
=> 
This is mathematically represented as
Where n is the number of moles which in this question is n = 1
So
=> 
So
=> 
=>
