1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
3 years ago
14

A sodium vapor lamp operates by using electricity to excite the highest-energy electron to the next highest-energy level. light

is produced when the excited electron drops back to the lower level. which two energy levels are involved in this process for the na atom?
Physics
1 answer:
viva [34]3 years ago
3 0

Answer:

The energy levels are: 3s and 3p

Explanation:

<u>The sodium (Na) element, with atomic number 11 (number of protons: Z=11), has the next electronic configuration</u>:  

Z=11:  1s² 2s² 2p⁶ 3s¹ = [Ne] 3s¹    

<u>Hence, the electricity used in a sodium vapor lamp will</u> excite the electron of the energy state n=3 from the s-orbital to the next highest energy p-orbital <u>which then</u> drops back to the lower energy s-orbital by the emission of a photon <u>resulting in the production of light</u>.      

<u />

<u>The transition of the electron is</u>:

Excitation: [Ne] 3s¹ → [Ne] 3s⁰ 3p¹

Emission: [Ne] 3p¹ → [Ne] 3s¹                                                                    

So, the energy levels that are involved in the process are 3s and 3p.

Have a nice day!              

You might be interested in
Find the speed of a long distance runner who runs 30km in 6 hours
slava [35]

30mi/6hrs is a speed of 5 mph, which converts to a pace of 12 min/mi.

7 0
3 years ago
Read 2 more answers
11. A cyclist accelerates from 0 m/s to 10 m/s in 3 seconds. What is his acceleration ? Is this acceleration higher than that of
Marat540 [252]

a =  \frac{v - u}{t}

v = final velocity

u = initial velocity

t = time taken

the acceleration of the cyclist is

\frac{10 - 0}{3}  = 3.333333....

approximately 3.33 m/s^2

the acceleration of the car is

\frac{40 - 0 }{8}  = 5.0

5.0 m/s^2

5.0 > 3.33 \\ so \:  the \: answer  \: is \: no

6 0
3 years ago
When objects are forced to vibrate ( like when dropped onto a hard surface), they will do so at their
Marat540 [252]

They'll vibrate at their characteristic resonant frequency. That depends on the material the object is made of and its shape.


3 0
3 years ago
Why does a vibrating simple pendulum not to produce any sound
Gelneren [198K]
It does produce 'sound' ... a compression wave traveling through the air. But your ears don't hear a sound that's vibrating less than 20 or 30 times every second. If you could swing your pendulum that fast, you could hear the sound of its vibrations pushing the air around.
7 0
3 years ago
One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has
Mars2501 [29]

Answer:

6.86 m/s

Explanation:

This problem can be solved by doing the total energy balance, i.e:

initial (KE + PE)  = final (KE + PE). { KE = Kinetic Energy and PE = Potential Energy}

Since the rod comes to a halt at the topmost position, the KE final is 0. Therefore, all the KE initial is changed to PE, i.e, ΔKE = ΔPE.

Now, at the initial position (the rod hanging vertically down), the bottom-most end is given a velocity of v0. The initial angular velocity(ω) of the rod is given by ω = v/r , where v is the velocity of a particle on the rod and r is the distance of this particle from the axis.

Now, taking v = v0 and r = length of the rod(L), we get ω = v0/ 0.8 rad/s

The rotational KE of the rod is given by KE = 0.5Iω², where I is the moment of inertia of the rod about the axis of rotation and this is given by I = 1/3mL², where L is the length of the rod. Therefore, KE = 1/2ω²1/3mL² = 1/6ω²mL². Also, ω = v0/L, hence KE = 1/6m(v0)²

This KE is equal to the change in PE of the rod. Since the rod is uniform, the center of mass of the rod is at its center and is therefore at a distane of L/2 from the axis of rotation in the downward direction and at the final position, it is at a distance of L/2 in the upward direction. Hence ΔPE = mgL/2 + mgL/2 = mgL. (g = 9.8 m/s²)

Now, 1/6m(v0)² = mgL ⇒ v0 = \sqrt{6gL}

Hence, v0 = 6.86 m/s

4 0
3 years ago
Other questions:
  • If the world was not tilted, what would happen to the people living on Earth
    10·2 answers
  • Which of the following is not found in the nucleus of an atom?
    12·2 answers
  • An object of mass 100kg is released from rest and falls through a distance of 10m.what is the work done by gravity
    6·1 answer
  • 1. Say whether the following statements are true or false and explain why:
    9·1 answer
  • Jack and Jill exercise in a 25.0 m long swimming pool. Jack swims 9 lengths of the pool in 156.9 s ( 2 min and 36.9 s ) , wherea
    5·1 answer
  • AYUDA!!!!
    6·1 answer
  • A car travels at 90 km per hour how much distance in metre does the car travel in 25 seconds​
    14·1 answer
  • What do diffraction and refraction have in common? They both involve interference. They both involve wave interactions. They bot
    11·2 answers
  • Mechanical waves form when a source of energy causes a medium to what
    14·1 answer
  • The event in the life of a star that begins its expansion into a giant is Group of answer choices almost all the hydrogen in its
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!