Velocity = displacement / time
v = 6 / 3/4
v = 6*4/3
v = 24/3
v = 8 m/s toward north
In short, Your Answer would be 8 m/s north
Hope this helps!
Answer:
Im just here for the points man sorry
Explanation:
You faded out there before asking your question.
Here's some info that might be of interest:
Torque = (force) x (distance from the pivot) = (10 n) x (0.9 m) = 9 newton-meters
Answer:
a) 14.2 atm
b) 4.46 atm
c) 1.06 atm
Explanation:
For an ideal gas,
PV = nRT
P = pressure of the gas
V = volume occupied by the gas
n = number of moles of the gas
R = molar gas constant = 0.08206 L.atm/mol.K
T = temperature of the gas in Kelvin
a) For HF,
P =?, V = 2.5L, n = 1.35 moles, T = 320K
P = 1.35 × 0.08206 × 320/2.5
P = 14.2 atm
b) For NO₂
P =?, V = 4.75L, n = 0.86 moles, T = 300K
P = 0.86 × 0.08206 × 300/4.75
P = 4.46 atm
c) For CO₂
P =?, V = 5.5 × 10⁴ mL = 55L, n = 2.15 moles, T = 57°C = 330K
P = 2.15 × 0.08206 × 330/55
P = 1.06 atm
