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tamaranim1 [39]

3 years ago

9

How is an anion formed?

2 answers:

Trava [24]3 years ago

7 0

Answer:

Cations (positively-charged ions) and anions (negatively-charged ions) are formed when a metal loses electrons, and a nonmetal gains those electrons. The electrostatic attraction between the positives and negatives brings the particles together and creates an ionic compound, such as sodium chloride.

Explanation:

Licemer1 [7]3 years ago

6 0

Answer:

anions are formed through the gains of electrons.

Explanation:

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The metal ions in iron are held together by

Sidana [21]

Metals are giant structures of atoms held together by metallic bonds. “Giant” implies that large but variable numbers of Atoms are involved - depending on the size of the bits of metal. most metals are close packed - that is, they fit as many items as possible into the available volume.

5 0

3 years ago

A thin beam of light of wavelength 50 μm (in the infrared portion of the em spectrum) goes through

Brut [27]

Solution :

Given :

Wavelength of the thin beam of light, λ = 50 μm

Distance of the screen from the slit, D = 3.00 m

Width of the fringe, Δy = ±8.24 mm

Therefore, width of the slit is given by :

$d=\frac{n \lambda D}{\Delta y}$

$=\frac{2 \times 50 \times 10^{-9} \times 3}{2 \times 8.24 \times 10^{-3}}$

= 0.000018203 m

= 0.0182 mm

= 0.018 mm

The intensity of light is given by :

$I=I_0\left(\frac{\sin \beta /2}{\beta/ 2}\right)^2$ , where $\beta=\frac{2 \pi D \sin \theta}{\lambda}$

$I=I_0\left(\frac{\sin \frac{\pi d \sin \theta}{\lambda}}{\frac{\pi d \sin \theta}{\lambda}}\right)^2$

$I=I_0\left(\frac{\sin \frac{\pi d y}{D\lambda}}{\frac{\pi d y}{D\lambda}}\right)^2$

Now, $\frac{dy}{D \lambda} = \frac{8.24 \times 10^{-3}\times 0.018 \times 10^{-3}}{4 \times 50\times 10^{-9}\times 4}$

= 0.1854

≈ 0.18

$I=I_0\left(\frac{\sin 0.56}{0.56}\right)^2$

$=I_0 \times 0.81$

= 2 x0.81

$= 1.62 \ W/m^2$

6 0

3 years ago

If it takes 0.5 seconds to travel 5 Millimeters? What's the mph?

Angelina_Jolie [31]

I think it would me 5/0.5 = 10mph

3 0

3 years ago

A venturi is constructed of a 10.0 cm pipe with a 2.0 cm diameter throat. Water pressure in the pipe is twice atmospheric pressu

postnew [5]

Answer:

$P_t=5066250.0696\ Pa=50\ atm$

Explanation:

Given:

diameter of pipe, $d=0.1\ m$

diameter of throat, $d_t=0.02\ m$

velocity of flow, $v=0.4\ m.s^{-1}$

<u>Pressure in the pipe is twice the atmospheric pressure:</u>

$P=2\times 101325=202650\ Pa$

<u>Now the force of flow of water:</u>

$F=P\times A$

<u>now we find cross sectional area of the pipe:</u>

$A=\frac{\pi.d^2}{4}$

$A=\pi \times\frac{0.1}{4}$

$A=0.007854\ m^2$

<u>Therefore,</u>

$F=202650\times 0.007854$

$F=1591.6094\ N$

<u>Now the area at throat:</u>

$A_t=\frac{\pi.d_t^2}{4}$

$A_t=\frac{\pi\times 0.02^2}{4}$

$A_t=0.000314\ m^2$

<u>Therefore pressure at throat:</u>

$P_t=\frac{F}{A_t}$

$P_t=\frac{1591.6094}{0.000314}$

$P_t=5066250.0696\ Pa=50\ atm$

6 0

3 years ago

A radioactive isotope has a life for 15 minutes. It has an initial count rate of 36000 Bg. What will the count be after 1 hour?

lukranit [14]

Answer:

18000 Bg

Explanation:

after 15 minutes = 36000/2

After 30 minutes = 36000/4

30 minutes × 2 = 1 hour

After 1 hour = 36000/4 × 2 = 18000 Bg

3 0

2 years ago