Number of moles of oxygen = x
number of moles of nitrogen = y
x = 2y
initial pressure, p1 = 0.8 atm
final pressure, p2 = 1.10 atm
At constant volume and temperature p1 / n1 = p2 / n2
=> p1 / p2 = n1 / n2
n1 = x + y = 2y + y = 3y
n2 = 0.2 + 3y
=> p1 / p2 = 3y / (0.2 + 3y)
=> 0.8 / 1.10 = 3y / (0.2 + 3y)
=> 0.8 (0.2 + 3y) = 1.10 (3y)
0.16 + 2.4y = 3.3y
=> 3.3y - 2.4y = 0.16
=> 0.9y = 0.16
=> y = 0.16 / 0.9
=. x = 2*0.16/0.9 = 0.356
Answer: 0.356 moles O2
Answer:
The acid will be neutralized overtime
Explanation:
The presence of the pyrites leads to the leaching of large amounts of sulphuric acid, however the basic carbonates neutralizes the acid according to the reaction equation;
CaCO3 + H2SO4 ---> CaSO4 + CO2 + H2O.
This will prevent all the deleterious consequences associated with the leaching of the acid in the abandoned coal mine.
Answer:
yes 4K + O2 ------>2K20 is true.
Answer:
Here
Explanation:
This is an acid-base reaction (neutralization): CaCO3 is a base, HCl is an acid.
Fe O
2 3 is what i would put
