What is the average rate of change of f(x), represented by the graph, over the interval [-2, 2)?

A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum

s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle= $q=-2.74\times 10^{-6} C$

Kinetic energy of particle= $K_E=6.65\times 10^{-10} J$

Initial time= $t_1=6.36 s$

Final potential difference= $V_2=0.351 V$

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

$qV=K.E$

Using the formula

$2.74\times 10^{-6}V_1=6.65\times 10^{-10} J$

$V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V$

Initial voltage= $V_1=2.43\times 10^{-4} V$

$\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2$

Using the formula

$\frac{V_1}{V_2}=(\frac{6.36}{t})^2$

$\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}$

$t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}$

$t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}$

$t=241.7 s$

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0

3 years ago

The dark fringe for m = 0 in a young's double-slit experiment is located at an angle of θ = 15°. What is the angle that locates

Ad libitum [116K]

The dark fringe for m = 0 in a young's double-slit experiment is located at an angle. The angle that locates the dark fringe for m = 1 is 51°.

<h3>What is dark fringe?</h3>

When light passes through a slit , it produces a spectrum which can be seen on the screen kept a distance in form of fringes of different intensity. The fringe with intensity zero is called the dark fringe.

Given is the angle θ = 15°

The equation for the dark fringe is

d sinθ = (m + 1/2)λ

For m= 0 and m=1, the ratio of the sines is

sinθ₁/sinθ₀ = [(m + 1/2)] / [(m + 1/2)]

Rearranging for sinθ₁, we have

sinθ₁ = [(m + 1/2)] / [(m + 1/2)] (sinθ₀)

Substituting the values into the equation and solving for θ₁

sinθ₁ = [1+1/2]/[0+1/2] (sin15)

θ₁ = 51°

Thus, the angle that locates the dark fringe fro m = 1 is 51°.

Learn more about dark fringe.

brainly.com/question/14098517

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6 0

3 years ago

Read 2 more answers

Given that:<br><br> = 2i + 9j ; and ⃗ = -i – 4j . Find . ⃗

Marat540 [252]

Answer:

A.B = -38

Explanation:

A = 2i + 9j and B = -i - 4j.

So, A.B = (2i + 9j).(-i - 4j)

= 2i.(-i) + 2i.(-4j) + 9j.(-i) + 9j.(-4j)

= -2i.i - 8i.j - 9j.i - 36j.j

since i.i = 1, j.j = 1, i.j = 0 and j.i = 0, we have

A.B = -2(1) - 8(0) - 9(0) - 36(1)

A.B = -2 - 0 - 0 - 36

A.B = -38

5 0

3 years ago

1.00 x 100 kg of clear liquid (specific heat

Gwar [14]

Answer:

No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a ... to change 1 kg of liquid water at the normal boiling point (100ºC at atmospheric pressure) to steam (water vapor).

The melting point of lead is 327.3o C. Assume the final temperature of the system is T. Then the amount of energy released by the lead as it solidifies is. ΔQ = mleadLlead = 0.09 kg*(2.45*104 J/kg) = 2205 J

7 0

3 years ago

Need help with this science!!

noname [10]

Lol, I remember I helped my sister with this question but anyways, the card flew because of inertia and the quarter fell in the glass because of gravity :).

3 0

3 years ago