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deff fn [24]
3 years ago
10

A 0.0121-kg bullet is fired straight up at a falling wooden block that has a mass of 4.99 kg. The bullet has a speed of 898 m/s

when it strikes the block. The block originally was dropped from rest from the top of a building and had been falling for a time t when the collision with the bullet occurs. As a result of the collision, the block (with the bullet in it) reverses direction, rises, and comes to a momentary halt at the top of the building. Find the time t.
Physics
1 answer:
aliya0001 [1]3 years ago
7 0

Answer:

t = 0.11 s

Explanation:

The motion is complete inelastic so the motion can be model using

mb * vb + mB * vB = ( mb + mB ) vf

mb = 0.0121 kg ,  mB = 4.99 kg ,  vb = 898 m / s , vB = 0

Replacing to find vf

0.0121 * 898 m / s + 4.99 kg * 0 = ( 0.0121 + 4.99) * vf

vf = 2.18 m / s

Now to find the time take the acceleration as a= g = 9.8 m /s²

t = mb * vb / a * (mb + 2 * mB)

t = [0.0121 kg * 898 m /s] / 9.8 * ( 0.0121 kg + 2*4.99)

t = 0.11 s

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Does uranium use steam?
Neko [114]

Answer:

Yes.

Explanation:

Reactors use uranium for nuclear fuel. The uranium is processed into small ceramic pellets and stacked together onto sealed metal tubes called fuel rods. The heat created by fission turns the water into steam.

4 0
3 years ago
In a low-density cloud, the internal pressure is much too low to support the weight, so the cloud must __________, eventually pr
andrey2020 [161]

The answer to this question is flatten

so the cloud must <u>flatten</u> eventually producing the galaxy s disk.

3 0
3 years ago
As the concentration of a solute in a solution increases, the freezing point of the solution ________ and the vapor pressure of
kykrilka [37]

Answer:

As the concentration of a solute in a solution increases, the freezing point of the solution <u><em>decrease </em></u>and the vapor pressure of the solution <em><u>decrease </u></em>.

Explanation:

Depression in freezing point :

\Delta T_f=K_f\times m

where,

\Delta T_f =depression in freezing point =  

K_f = freezing point constant  

m = molality  ( moles per kg of solvent) of the solution

As we can see that from the formula that higher the molality of the solution is directly proportionate to the depression in freezing point which means that:

  1. If molality of the solution in high the depression in freezing point of the solution will be more.
  2. If molality of the solution in low the depression in freezing point of teh solution will be lower .

Relative lowering in vapor pressure of the solution is given by :

\frac{p_o-p_s}{p_o}=\chi_{solute}

p_o = Vapor pressure of pure solvent

p_s  = Vapor pressure of solution

\chi_{solute} = Mole fraction of solute

p_s\propto \frac{1}{\chi_{solute}}

Vapor pressure of the solution is inversely proportional to the mole fraction of solute.

  1. Higher the concentration of solute more will the be solute's mole fraction and decrease in vapor pressure of the solution will be observed.
  2. lower the concentration of solute more will the be solute's mole fraction and increase in vapor pressure of the solution will be observed.
8 0
3 years ago
Lukalu is rappelling off a cliff. The parametric equations that describe her horizontal and vertical position as a function of t
andre [41]

Answer:

2.5 s, 5 m

Explanation:

The equations for the horizontal and vertical position of Lukalu are:

x(t) = 8t\\y(t) = -16t^2 + 100

we can find the time it takes her to reach the ground by requiring that the vertical position becomes zero:

y(t) = 0

So we find:

0=-16t^2 +100\\16t^2 = 100\\t=\sqrt{\frac{100}{16}}=2.5 s

The horizontal distance of Lukalu instead will be given by the equation for the horizontal position, substituting t = 2.5 s:

x=8t = 8 \cdot 2.5 s =5 m

4 0
3 years ago
A student measures the mass 8cm block of brown sugar to be 12.9g. what is the density of the brown sugar.
antoniya [11.8K]

Correction

A student measures the mass <em><u>8cm3</u></em> block of brown sugar to be 12.9g. what is the density of the brown sugar

Answer:

1.6\ g/cm^{3}

Explanation:

Density is defined as mass per unit volume of an object expressed as \rho=\frac {m}{v} where \rho is the density, m is the mass of sugar and v is the volume of the sugar. Considering that the volume is given as 8cm3 for sugar then we substitute this for v and mass of 12.9 g we substitute for g then the density will be

\rho=\frac {12.9 g}{8 cm3}=1.6125\ g/cm^{3}\approx 1.6\ g/cm^{3}

8 0
3 years ago
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