How much a material takes time to burn?

A 25.0 mL sample of 0.100 M lactic acid (HC3H503, Ka = 1.4 E-4) is titrated with 0.100 M NaOH solution. Calculate the pH of the

aleksklad [387]

I’m a bit confused too

4 0

3 years ago

A mixture of H2 and water vapor is present in a closed vessel at 20. 00°C. The total pressure of the system is 755. 0 mmHg. The

MAVERICK [17]

The partial stress of H2 is 737.47 mmHg Let's observe the Ideal Gas Law to find out the whole mols.

We count on that the closed vessel has 1L of volume

P.V=n.R.T
We must convert mmHg to atm. 760 mmHg.
1 atm
755 mmHg (755/760) = 0.993 atm
0.993 m.1L=n.0.082 L.atm/mol.K .
293 K(0.993 atm 1.1L)/(0.082mol.K /L.atm).
293K = n
0.0413mols = n

These are the whole moles. Now we are able to know the moles of water vapor, to discover the molar fraction of it.

P.V=n.R.T
760 mmHg. 1 atm
17.5 mmHg (17.5 mmHg / 760 mmHg)=0.0230 atm
0.0230 m.1L=n.0.082 L.atm/mol.K.293 K(0.0230atm.1L)/(0.082mol.K/L.atm .293K)=n 9.58 × 10 ^ 4 mols = n.
Molar fraction = mols )f gas/general mols.
Molar fraction water vapor =9.58×10^ -four mols / 0.0413 mols
Sum of molar fraction =1
1 - 9.58 × 10 ^ 4 × mols / 0.0413 ×mols = molar fraction H2
0.9767 = molar fraction H2
H2 pressure / Total pressure =molar fraction H2
H2 pressure / 55mmHg = =0.9767 0.9767 = h2 pressure =755 mmHg.
737,47 mmHg.

<h3>What is a mole fraction?</h3>

Mole fraction is a unit of concentration, described to be identical to the variety of moles of an issue divided through the whole variety of moles of a solution. Because it's miles a ratio, mole fraction is a unitless expression.

Thus it is clear that the partial pressure of H2 is 737,47 mmHg.

To learn more about partial pressure refer to the link :

brainly.com/question/19813237

<h3 />

5 0

2 years ago

What type of substance contains more than one kind of element joined by chemical bonds?

Usimov [2.4K]

The answer is compound. Elements are composed of one kind of atoms bonded together. There are different types of compounds: ionic, complexes, molecular, and intermetallic compounds. The proportion of elements in the compound is expressed using a chemical formula. An example of an element is Aluminium while an example of a compound is H2S (Hydrogen sulfide).

3 0

3 years ago

Determine the primary structure of an octapeptide from the following data: acid-catalyzed hydrolysis gives 2 arg, leu, lys, met,

erma4kov [3.2K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The sequence of these amino acid would be

Lue Arg Lys Arg Met Phe Arg Ser

Explanation:

The acid-catalyzed hydrolysis from makes us to understand that the polypeptides contains 8 amino acids

From the question we are told that the Edman's reagent releases Leu it means that the N-terminal amino acid would be Lue(i.e Leucine)

Also from the question we are told that the Carboxypeptidase released Ser this mean the the C-terminal amino acid would be Ser ( i.e Serine)

The Amino acids would in the polypeptides would be arranged like this

Lue __ __ __ __ __ __ Ser

Now from the question we are told that treatment with cranogen bromide form two peptides.

Now generally cranogen bromide divides a peptide on the C- side(i.e the extreme left side ) of Met(Methionine)(This is an amino acid obtained by hydrolysis of most common peptides )

So this means that any peptides containing Met(Methionine) must have Methionine as a C- terminal amino acid(i.e at extreme left) and for peptides that does not contain Met must be C - terminal peptides

From the question we see that it is the second peptide that contain Met and it is a penta peptide(i.e it contains 5 amino acid)

Thus the fifth amino acid is Met

So the sequence of these amino acid would now be

Lue __ __ __ Met __ __ Ser

From the question we are told that the the Trypsin-catalyzed hydrolysis forms two amino acid and two peptides

Now generally Trypsin divides a peptide on the C- side(i.e the extreme left) of Arg(Arginine) and Lys (lysine) and any peptide that holds Arg or Lys must have them as their C- terminal amino acids

From the first peptide in the two peptide formed we see that Arg would be the Seventh amino acid of the octapeptide because commonly the trypsin that sticks to the C-side of Arg would for Ser

and Phe would be the sixth amino acid of the octapeptide

So the sequence of these amino acid would be

Lue __ __ __ Met Phe Arg Ser

Looking at the first amino acid formed from the Trypsin-catalyzed hydrolysis we see that Arg would be the fourth amino acid of octapeptide as Trypsin divides a peptide on the C- side(i.e the extreme left) of Arg(Arginine).

From the second peptide of the Trypsin-catalyzed hydrolysis we see that Lys would be the third amino acid of the octapeptide as trypsin divides on the C- side of Lys (lysine) and Tyr would be the second amino acid of the octapeptide

So the sequence of these amino acid would be

Lue Arg Lys Arg Met Phe Arg Ser

4 0

3 years ago

In an oxidation half-reaction, which amount is shown?

Tatiana [17]

Hi,
The answer should be C.

Hope this helps, if you’d like further explanation please let me know.

4 0

3 years ago

Read 2 more answers