Answer: (1). There are 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP.
(2). The density of gaseous arsine is 3.45 g/L.
Explanation:
1). At STP the pressure is 1 atm and temperature is 273.15 K. So, using the ideal gas equation number of moles are calculated as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
2). As number of moles are also equal to mass of a substance divided by its molar mass.
So, number of moles of Arsine (molar mass = 77.95 g/mol) is as follows.
Density is the mass of substance divided by its volume. Hence, density of arsine is calculated as follows.
Thus, we can conclude that 0.0165 moles of gaseous arsine (AsH3) occupy 0.372 L at STP and the density of gaseous arsine is 3.45 g/L.
Answer:
Na2SO3 + H2O2 = Na2SO4 + H2O
Explanation:
Chemical reaction and equation.
I think it's easiest to find the pOH from the given [OH-] first.
-log(1x10^-5)
pOH=5
Then find the pH.
pOH+pH=14
5+pH=14
pH=9
Then find the [H+] using the pH.
antilog(-9) (if you dont have an antilog button use 10^-9)
[H+]=1x10^-9
Answer:
The density of the pebble is 0.483g/mL (rounded), but it's 0.48333333333333 without rounding. Hope this helped! :)
Explanation:
Volume= 6.0mL Density=Mass/Volume
Mass= 2.9g
D=2.9g/6.0mL
D=0.48333333333333g/mL
<em> or</em>
D≈0.483g/mL
Answer:
H₂O = 3.56 moles
MgCl₂ = 1.78 moles
Explanation:
Given data:
Moles of HCl = 3.56 mol
Moles of water produced = ?
Moles of MgCl₂ produced = ?
Solution:
Chemical equation:
2HCl + Mg(OH)₂ → MgCl₂ + 2H₂O
Now we will compare the moles of HCl with water and magnesium chloride.
HCl : MgCl₂
2 : 1
3.56 : 1/2×3.56 = 1.78 mol
HCl : H₂O
2 : 2
3.56 : 3.56 mol