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3 years ago

Why do we use conversion factors instead of just multiplying or dividing as needed? What’s the advantage?

1 answer:

4 0

If you’re referring to stoichiometry, which usually involves the long t-tables of multiple conversions, then you’re not alone in wondering the purpose of using them. The purpose of conversion tables is to help keep track of what you’re doing. When quickly converting one value to another, it’s very easy to forget a particular piece to the puzzle, or to use a factor that doesn’t work for that instance. Teachers usually draw out a t-table every time they work a problem so as not to confuse students, but anytime you’re working with funky units or converting across systems (metric to imperial and vice versa) it’s a good idea to use them.

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What is the original source of energy that is stored in the food that animals eat?

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3 years ago

Each equation is incorrect. find the errors, then rewrite and balance each equation. cl2 + nai → nacl2 + i nh3 → n + h2 na + o2

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3 years ago

What property is primarily responsible for determining the type of electromagnetic energy and peak wavelength emitted by a star

svetoff [14.1K]

The answer i think it is... is Temperature
Hope this helped!

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4 years ago

Read 2 more answers

How many moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 ATM

Rama09 [41]

Answer:

285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

P= 200.8 atm
V= 35 L
n=?
R= 0.082 $\frac{atm*L}{mol* K}$
T= 27.3 C= 300.3 K (being O C= 273 K)

Replacing:

200.8 atm* 35 L= n* 0.082 $\frac{atm*L}{mol* K}$ * 300.3 K

Solving:

$n=\frac{200.8 atm* 35 L}{0.082\frac{atm*L}{mol* K} * 300.3 K}$

n= 285.4 moles

285.4 moles of gas are in a 35.0 L scuba canister if the temperature of the canister is 27.3 °C and the pressure is 200.8 atm.

5 0

3 years ago

From these two reactions at 298 K, V2O3(s) + 3CO(g) → 2V(s) + 3CO2(g); ΔH° = 369.8 kJ; ΔS° = 8.3 J/K V2O5(s) + 2CO(g) → V2O3(s)

gregori [183]

Answer:

ΔG° = -133,1 kJ

Explanation:

For the reactions:

(1) V₂O₃(s) + 3CO(g) → 2V(s) + 3CO₂(g); ΔH° = 369,8 kJ; ΔS° = 8,3 J/K

(2) V₂O₅(s) + 2CO(g) → V₂O₃(s) + 2CO₂(g); ΔH° = –234,2 kJ; ΔS° = 0,2 J/K

By Hess's law it is possible to obtain the ΔH° and ΔS° of:

2V(s) + 5CO₂(g) → V₂O₅(s) + 5CO(g)

Substracting -(1)-(2), that means:

ΔH° = -369,8 kJ - (-234,2 kJ) = -135,6 kJ

ΔS° = - 8,3 J/K - 0,2 J/K = -8,5 J/K

Using: ΔG° = ΔH° - TΔS° at 298K

ΔG° = -135,6 kJ - 298K×-8,5x10⁻³kJ/K

ΔG° = -133,1 kJ

I hope it helps!

7 0

4 years ago