Answer:
m = 35.98 Kg ≈ 36 Kg
Explanation:
I₀ = 125 kg·m²
R₁ = 1.50 m
ωi = 0.600 rad/s
R₂ = 0.905 m
ωf = 0.800 rad/s
m = ?
We can apply The law of conservation of angular momentum as follows:
Linitial = Lfinal
⇒ Ii*ωi = If*ωf <em>(I)</em>
where
Ii = I₀ + m*R₁² = 125 + m*(1.50)² = 125 + 2.25*m
If = I₀ + m*R₂² = 125 + m*(0.905)² = 125 + 0.819025*m
Now, we using the equation <em>(I) </em>we have
(125 + 2.25*m)*0.600 = (125 + 0.819025*m)*0.800
⇒ m = 35.98 Kg ≈ 36 Kg
Answer:
The emf is 0.574 volt.
Explanation:
Given that,
Magnetic field
Length = 75.0 m
Velocity = 255 m/s
We need to calculate the emf
Using formula of emf
Where, v = velocity
l = length
B = magnetic field
Put the value into the formula
Hence, The emf is 0.574 volt.
<span>Angular distance moved = 220 rad = {35(2π) ≈ 220 rad}
Max angular speed = 18 rad/s
Final angular speed = 0 rad/s
Avg angular speed = 9 rad/s {assuming a CONSTANT de-celeration of wheel}
Time to stop = 220/9 = 24.4 s ANS</span>
Answer:
Personally I think, that the answer is B.
Explanation: