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Vlad [161]
3 years ago
8

If a drug caused a sudden release of large amounts of calcium in skeletal muscle, from which structure would the calcium come?

Chemistry
2 answers:
lawyer [7]3 years ago
7 0
<span>Sarcoplasmic reticulum</span>
ser-zykov [4K]3 years ago
4 0

Answer:

The correct answer will be option-sarcoplasmic reticulum.

Explanation:

The sarcoplasmic reticulum is the membrane bound endoplasmic reticulum of the muscle cell which stores a large amount of Ca⁺² ions.

The reticulum contains Calsequestrin- a calcium binding protein which binds around 50 Ca⁺² ions to itself and helps store more calcium. These calcium ions are released when the signals through T-tubules are carried to the reticulum which leads to the opening of the calcium channels.

Thus, sarcoplasmic reticulum is the correct answer.

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a. Calculate the pH of a solution that has [H3O+]= 4.3 x 10-5 M. b. Is the solution acidic or basic? How do you know?
Luda [366]

Answer:

* pH=4.37

* The solution is acidic since the pH is below 7.

Explanation:

Hello,

In this case, we can mathematically define the pH by:

pH=-log([H_3O^+])

Thus, for the given hydronium concentration we simply compute the pH:

pH=-log(4.3x10^{-5})=4.37

Thereby, we conclude the solution is acidic due to the fact that the pH is below 7 which is the neutral point and above it the solutions are basic.

Regards.

3 0
3 years ago
The process of splitting and Atom into two lighters atoms is called?
natima [27]
<span>The process of splitting and Atom into two lighters atoms is called </span>Nuclear Fission
5 0
3 years ago
6. The modern view of the atom has come a long way from that of a solid, indestructible sphere
Fynjy0 [20]
It is a true statement
4 0
3 years ago
PLEASE HELP MEEE!!!!
Assoli18 [71]
It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.
3 0
3 years ago
If 2 CH3OH + 3 O2 -&gt; 2CO2 + 4 H2O was carried out in the laboratory and 219 g of water was produced, what would the percent y
ANEK [815]

Answer:

Percent yield = 84.5 %

Explanation:

Given data:

Mass of methanol = 229 g

Actual yield of water = 219 g

Percent yield of water = ?

Solution:

Chemical equation:

2CH₃OH + 3O₂  →  2CO₂  + 4H₂O

Number of moles of methanol:

Number of moles = mass/ molar mass

Number of moles = 229 g/ 32 g/mol

Number of moles = 7.2 mol

Now we will compare the moles of water with methanol.

                        CH₃OH         :            H₂O

                            2               :               4

                           7.2             :           4/2×7.2 = 14.4 mol

Mass of water:

Mass = number of moles × molae mass

Mass = 14.4 mol × 18 g/mol

Mass = 259.2 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 219 g / 259.2 g × 100

Percent yield = 84.5 %

7 0
3 years ago
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