Answer: 0.2885J/g°c
Explanation:
Loss of heat of metal = Gain of heat by the water
Therefore
-Qm = +Qw
Where
Q = mΔTCp
Q = heat
M= mass
ΔT = T.f - Ti
Ti= initial temperature
T.f= final temperature
Cp= Specific heat (m is metal, w is water)
-Qm = +Qw
-[m(T.f-Ti)Cpm] = m(T.f-Ti)Cpw
Therefore
-[83.2g(28.42-90.31)Cpm] = 41.82g(28.42-
19.93)4.194J/g°c
Cpm = 1485.54÷ 5149.25
Cpm = 0.2885J/g°c
Therefore , the specific heat of the metal is 0.2885J/g°c
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