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slamgirl [31]
3 years ago
5

What processes would cause increased abrasion along the coastal region? Explain.

Chemistry
1 answer:
Andreas93 [3]3 years ago
4 0
If you are talking about at the beaches waves would cause increased abrasion because the force of a wave hitting a rock or something else will slowly cause the object to wear away. Also strong winds could cause increased abrasion because the wind could pick up small sand particles that will slowly erode the thing it hits.
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Lori’s family is on a road trip. They split their drive into the five legs listed in the table. Find the average velocity for ea
lilavasa [31]

Answer:

The answer is E,B,A,C,D

7 0
3 years ago
Could someone help me with this too? Much appreciated! I am a bit stuck.
Mashcka [7]

Answer:

CO

Explanation:

4 0
3 years ago
What is the expected number of valence electrons in an atom of the element flerovium in ground state
ehidna [41]
Flerovium at its ground state is solid. It has electron configuration of [Rn]5f¹⁴6d¹⁰7s²7p². The expected number of valence electrons in a flerovium atom is 2. A ground state is the most stable state of an atom at satndard temperature and pressure.
7 0
3 years ago
Question 2
andrezito [222]

Answer:

A.  Peroxide breaking down into water and oxygen

Explanation:

Generally when it comes to changes, there are physical and chemical changes. In physical changes, there are no new substances been formed, however in chemical change new substances are formed.

A.  Peroxide breaking down into water and oxygen

This is a chemical change.

B . Bubbles forming when a pot of water is heated

This is a physical change

C. A pair of jeans soaked in water drying after hanging outside

This is a physical change

D . A block of ice decreasing in size due to a change in temperature

This is a physical change.

Only option A is different from the rest,hence this is the answer.

3 0
4 years ago
When 0.200 grams of Al reacts with 15.00 mL of a 0.500 M copper(II) chloride solution, how many moles of solid Cu would be produ
Naddik [55]
When The balanced equation is:
2Al + 3CuCl2 ⇒3 Cu + 2AlCl3
So, we want to find the limiting reactant:
1- no. of moles of 2Al = MV/n = (Wt * V )/ (M.Wt*n*V) = Wt / (M.Wt *n)
        
where M= molarity, V= volume per liter and n = number of moles in the balanced equation.
by substitute: 
∴ no. of moles of 2Al = 0.2 / (26.98 * 2)= 0.003706 moles.
2- no.of moles of 3CuCl2= M*v / n = (0.5*(15/1000)) / 3= 0.0025 moles.
So, CuCl2 is determining the no.of moles of the products.
∴The no. of moles of 3Cu = 0.0025 moles.
∴The no.of moles of Cu= 3*0.0025=  0.0075 moles.
and ∵ amount of weight (g)= no.of moles * M.Wt = 0.0075 * M.wt of Cu
 = 0.0075 * 63.546 =0.477 g


3 0
3 years ago
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