Calculate the theoretical yield in moles of magnesium chloride when 37 grams of Mg(s) react with 38 grams of HCl(aq).Write the a
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This is an incomplete question, here is a complete question.
Aqueous sulfuric acid (H₂SO₄) reacts with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na₂SO₄) and liquid water (H₂O) . If 12.5 g of water is produced from the reaction of 72.6 g of sulfuric acid and 77.0 g of sodium hydroxide, calculate the percent yield of water. Round your answer in significant figures.
Answer: The percent yield of water is, 46.8 %
Explanation : Given,
Mass of = 72.6 g
Mass of = 77.0 g
Molar mass of = 98 g/mol
Molar mass of = 40 g/mol
First we have to calculate the moles of and
.
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 1 mole of react with 2 mole of
So, 0.741 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 1 mole of react to give 2 mole of
So, 0.741 moles of react to give
moles of
Now we have to calculate the mass of
Molar mass of = 18 g/mole
Now we have to calculate the percent yield of water.
Now put all the given values in this formula, we get:
Thus, the percent yield of water is, 46.8 %