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Lelechka [254]
3 years ago
9

What minimum number of 45 W lightbulbs must be connected in parallel to a single 240 V household circuit to trip a 50.0 A circui

t breaker? ____lightbulbs
Physics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:267

Explanation:

Given

Power of light bulbs is 45 W

and voltage applied is 240 V

Allowable current is 50 A

and P=\frac{V^2}{R}

R=\frac{V^2}{P}

R=\frac{240\times 240}{45}=1280 \Omega

and wire will trip if resistance drop below

R_{total}=\frac{240}{50}=4.8 \Omega

Therefore R_{total}=\frac{R}{n}

n=\frac{R}{R_{total}}=\frac{1280}{4.8}=266.667 \approx 267

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3 years ago
Which best describes Earth's magnetic pole?
goblinko [34]

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Explanation:

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7 0
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The process of how rocks can tell us how old the earth is
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7 0
3 years ago
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boyakko [2]

Answer:

Check explanation

Explanation:

In the formation of calcium fluoride we take calcium and fluorine.

in elemental form calcium exist in solid form and fluorine in gaseous form.

formation of compound takes place to complete their octet, in case of calcium  need to remove two electron and need to add one elecron in fluorine to complete their octet so two electron will ransferred from calcium to two fluorine atom.  

3 0
3 years ago
A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction
Elis [28]

Answer:

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Let d be the distance covered by him in time, t s.

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The position-time graph has been shown.

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(b) Similarly, for t=15.0 s

d=5\times 15=75 m

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8 0
3 years ago
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