@AL2006 had answered this before: Well, first of all, wherever you got this question from has done
a really poor job of question-writing. There are a few assorted
blunders in the question, both major and minor ones:
-- 22,500 is the altitude of a geosynchronous orbit in miles, not km.
-- That figure of 22,500 miles is its altitude above the surface,
not its radius from the center of the Earth.
-- The orbital period of a synchronous satellite has to match
the period of the Earth's rotation, and that's NOT 24 hours.
It's about 3 minutes 56 seconds less ... about 86,164 seconds.
Here's my solution to the question, using some of the wreckage
as it's given, and correcting some of it. If you turn in these answers
as homework, they'll be marked wrong, and you'll need to explain
where they came from. If that happens, well, serves ya right for
turning in somebody else's answers for homework.
The satellite is traveling a circle. The circle's radius is 26,200 miles
(not kilometers) from the center of the Earth, so its circumference
is (2 pi) x (26,200 miles) = about 164,619 miles.
Average speed = (distance covered) / (time to cover the distance)
= (164,619 miles) / day
(264,929 km)
= 6,859 miles per hour
(11,039 km)
= 1.91 miles per second
(3.07 km)
Answer:
The spring constant of the spring is 47.62 N/m
Explanation:
Given that,
Mass that is attached with the spring, m = 29 g = 0.029 kg
The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,
f = 6.45 Hz
The frequency of oscillator is given by :
k is the spring constant
k = 47.62 N/m
So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.
<span>The amplitude. It is the displacement at a peak.</span>
Answer:
v² = u² + 2x²
Explanation:
v² = u² + 2as is only valid for constant acceleration. Here, the acceleration is a function of position. We can find the function of velocity by integrating. Acceleration is the derivative of velocity with respect to time:
a = 2x
dv/dt = 2x
Apply chain rule:
dv/dt = dx/dt × dv/dx
dv/dt = v × dv/dx
Therefore:
v dv/dx = 2x
Separate the variables and integrate:
v dv = 2x dx
½ v² |ᵤᵛ = x² |₀ˣ
½ (v² − u²) = x²
v² − u² = 2x²
v² = u² + 2x²
