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mars1129 [50]
3 years ago
15

You are driving your small, fuel-efficient car when you have a head-on collision with a big, fuel-efficient truck that is three

times as massive as your car. Head-on means, for example that if you are traveling in the positive x direction, the truck is traveling in the negative x direction. Right before the collision, you were traveling at a speed of 3.0 m/s and right after the collision, both vehicles are at rest. Due to the conservation of the momentum, you can find the speed of the truck before the collision. What was the kinetic energy of the truck Ktruck before the collision when the kinetic energy of the car was Kcar
Physics
1 answer:
Sindrei [870]3 years ago
3 0

Explanation:

Momentum before = momentum after

mv + MV = 0

(m) (3.0 m/s) + (3m) (V) = 0

V = -1.0 m/s

The truck was moving at 1.0 m/s before the collision.

The kinetic energy of the car was:

KE = 1/2 m v²

Kcar = 1/2 m (3.0)²

Kcar = 9/2 m

Ktruck = 1/2 M V²

Ktruck = 1/2 (3m) (1.0)²

Ktruck = 3/2 m

Ktruck = 1/3 Kcar

So the truck had 1/3 the kinetic energy of the car.

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w strong are you? Could you turn a moving car with just your own strength? No way! If a normal driver inputs about 50 N of force
malfutka [58]

The mechanical advantage of a simple machine is the measure of its amplified force gain.

The mechanical advantage  is defined as the force amplified by a machine to the force required to generate such output.

Mathematically\ mechanical\ advantage\ MA=\frac{F_{o}} {F_{i}}

F_{o} \ and\ F_{i} are the amplified force and applied force. We may also consider them as output and input force.          


In the given question, the force given to the steering wheel is 50 N.

The output force produced by the steering wheel is 3750 N.

Hence the mechanical advantage will be-

                               MA=\frac{F_{o}} {F_{i}}

                                       =\frac{3750\ N}{50\ N}

                                       =75      [ans]

3 0
3 years ago
A materials density is the same , no matter how large or small the sample is or what it’s shape is as long as it is solid unifor
Scorpion4ik [409]

Answer:

See the explanation below

Explanation:

Density is defined as the relationship between mass and volume, i.e. the following equation can be used:

density = m/v

where:

density [kg/m^3]

m = mass [kg]

v = volume [m^3]

If we change the volume of a body by reducing its size, its mass will also decrease proportionally with a density as seen in the equation.

m = density*v

To understand this concept more clearly, let's use the following example:

We know that the density of water is equal to 1000 [kg/m^3], that is, 1 cubic meter of water contains 1000 kilograms of water, using the equation.

1000 = m /1

m = 1000*1 = 1000 [kg]

Now if we have 500 kilograms of water, that would pass with the volume so that the density remains constant.

1000 = 500/v

v = 500/1000

v = 0.5 [m^3]

We can see that the volume of water has halved. Since the mass of water was reduced by half. That is, the relationship between mass and volume is proportional to the density of the material or substance.

8 0
3 years ago
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.2 rad/s in 3.07 s. (a) f
Hitman42 [59]
(a) The angular acceleration of the wheel is given by
\alpha =  \frac{\omega_f - \omega_i }{t}
where \omega_i and \omega_f are the initial and final angular speed of the wheel, and t the time.

In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
\alpha =  \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2

(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
\theta (t) = \omega_i t +  \frac{1}{2} \alpha t^2
where \omega_i = 0 is the initial angular speed. So, the angle covered after a time t=3.07 s is
\theta=  \frac{1}{2}  \alpha t^2 =  \frac{1}{2}(3.65 rad/s^2)(3.07 s)^2 = 17.2 rad
6 0
3 years ago
If the inside of a container has a surface area of 20cm², what will be the pressure on each square inch of the container if 117.
egoroff_w [7]

Answer:

Explanation:

given :-

force applied = 117.6N

Area = 20 m^2

Pressure =?

solution:-

Pressure = Force / Area

= 117.6 N / 20 m^2

= 5.88 Pascals

Hope it helps :D!

Explanation:

6 0
2 years ago
5. Кульки із сталі, чавуну, міді і латуні мають однакові розміри. Яка з них має
Oksanka [162]

Answer:

Sorry, I don't understand this language, sorry dear

4 0
3 years ago
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