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3 years ago

Real life example in which linear motion is not uniform motion.

Physics

1 answer:

wlad13 [49]3 years ago

5 0

1. A horse running in a race
2. A car in traffic
3. Movement of an asteroid
4. A car coming to a halt

Hope this helped

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Make the following conversion

ValentinkaMS [17]

Answer:

The value of 60.2 mg in to g is 0.0602.

Explanation:

We need to calculate the 60.2 mg in to gram.

Conversion mg to g :

1 g = 1000 mg

Using this conversion,

$1 mg = 10^{-3}g$

So, $60.2\ mg = 60.2\times10^{-3}\ g$

$60.2\times10^{-3}\ g$

Hence, The value of 60.2 mg in to g is 0.0602.

4 0

3 years ago

The distance from the Moon to Earth is 3.9 x 10^8 meters. What is the time required for a light ray to travel from the Moon to E

kondaur [170]

Answer:

hello I don't know the answer sorry next time I will try

6 0

2 years ago

A 5.7 kg block attached to a spring executes simple harmonic motion on a frictionless horizontal surface. At time t = 0s, the bl

Genrish500 [490]

Answer:

Explanation:

Given

mass of block $m=5.7\ kg$

at $t=0 s$

displacement is $x=-0.7\ m$

velocity $v=-0.8\ m/s$

acceleration $a=2.7\ m/s^2$

suppose $x=A\cos (\omega t+\phi )$ is the general equation of SHM

where A=amplitude

$\omega$ =natural frequency of oscillation

therefore velocity and acceleration is given by

$v=-A\omega \sin (\omega t+\phi )$

$a=A\omega ^2\cos (\omega t+\phi )$

for t=0

$-0.7=A\cos (\phi )---1$

$v=-0.8=-A\omega \sin(\phi)---2$

$a=2.7=-A\omega ^2\cos(\phi )----3$

divide 1 and 3 we get

$\omega ^2=\frac{27}{7}$

$\omega =\sqrt{\frac{27}{7}}$

Now square and 1 and 2 we get

$(0.7)^2+(\frac{0.8}{\omega })^2=A^2$

$A^2=0.49+0.166$

$A=0.81\ m$

3 0

3 years ago

A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed.

motikmotik

You have to find the calculate the circumference first then you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each revolution. Then you can multiply by the number of revolutions per minute.

3 0

2 years ago

What is the relationship between the mass of the objects and the force exerted?

pishuonlain [190]

Answer:

Objects with mass exert forces on each other via the force of gravity. This force is proportional to the mass of the two interacting objects, and is inversely proportional to the square of the distance between them. The factors G, M, and r are the same for all masses at the surface of the Earth.

3 0

3 years ago