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vaieri [72.5K]
3 years ago
5

The bubbles in a carbonated soft drink are produced when carbonic acid decomposes to form carbon dioxide and water. In a closed

system, this equilibrium exists as
Why does a carbonated soft drink lose carbonation when the container is left open?


A.Water evaporates, which favors the formation of H2CO3.

B.Pressure decreases, which favors the formation of H2CO3.

C.The open container warms up, which causes more gas to escape.

D.CO2is removed, which favors the formation of H2CO3.
Physics
1 answer:
nika2105 [10]3 years ago
6 0

<u>Answer:</u>

The bubbles in a carbonated soft drink show up when carbonic acid (H2CO3) decomposes to form carbon dioxide (CO2) and water (H2O). In a closed system, this equilibrium exists as:

                                         H2CO3 ⇌ CO2+ H2O


B is the correct answer.

Carbonated drinks are sealed under high pressure so when a container is left open, pressure decreases which favors the formation of carbonic acid (H2CO3). It is weak acid which decomposes releasing CO2 in the form of bubbles.  


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The speed of the toy when it hits the ground is 2.97 m/s.

The given parameters;

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The speed of the toy before it hits the ground will be maximum. Apply the principle of conservation of mechanical energy to determine the maximum speed of the toy.

P.E = K.E

mgh_{max} = \frac{1}{2} mv_{max}^2\\\\gh_{max} = \frac{1}{2} v_{max}^2\\\\v_{max}^2= 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}}

Substitute the given values and solve the speed;

v_{max} = \sqrt{2\times 9.8 \times 0.45} \\\\v_{max} = 2.97 \ m/s

Thus, the speed of the toy when it hits the ground is 2.97 m/s.

Learn more here: brainly.com/question/7562874

7 0
3 years ago
Two identical freight cars roll without friction (one at 1 m/s, the other at 2 m/s) toward each other on a level track. They col
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Answer:

They collide, couple together, and roll away in the direction that <u>the 2m/s car was rolling in.</u>

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We should start off with stating that the conservation of momentum is used here.

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Since, mass of both freight cars is the same, the speed determines which has more momentum.

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The final speed is calculated as below:

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Let's substitute the velocities 1m/s for the first car, and - 2m/s for the second. (since the second is opposite in direction)

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V = - 0.5 m/s

Thus we can see that both cars will roll away in the direction that the 2 m/s car was going in. (because of the negative sign in the answer)

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To solve this problem, we must remember about the law of conservation of momentum. The initial momentum mist be equal to the final momentum, that is:

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Since we are not given the masses of each car m1 and m2, so let us assume that they are equal, such that:

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