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Irina-Kira [14]
3 years ago
7

In step 6, khp was dissolved in a trivial amount of deionized h2o prior to titration with naoh. why was it acceptable to use an

approximate volume of h2o when this solution was used to determine the exact amount of naoh that was neutralized?
Chemistry
1 answer:
nadya68 [22]3 years ago
6 0
Water acts as solvent and it has no effect on the amount of the acid or the titrating agent. 
<span>Also, the concentration of the titrating agent must be known exactly, the amount of solvent is less important (the more diluted it is, the more accurate is the titration).</span>
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Question options:

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<u>Therefore, a substance is soluble in a particular liquid if it is able to dissolve in a solvent.</u>

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The rate of a reaction is measured by how fast a reactant is used up to how fast a product is formed.
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Which of the following elements has the highest electronegativity?
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Explain how you would test the presence of oxygen and hydrogen gases. ​
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3 years ago
What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?
djverab [1.8K]

The empirical formula of the compound is CHCl₃.

<h3>Calculation:</h3>

Given,

Mass of carbon = 5.03 g

Mass of hydrogen = 0.42 g

Mass of chlorine = 44.5 g

Molecular weight of carbon = 12 g

Molecular weight of hydrogen = 1 g

Molecular weight of chlorine = 35.4 g

First, calculate the moles of each element,

                      Moles = given mass/ molecular weight

Moles of carbon = 5.03/12 = 0.42

Moles of hydrogen = 0.42/1 = 0.42

Moles of chlorine = 44.5/ 35.4 = 1.26

Divide the moles of each element by the smallest number of moles,

0.42 mol of C/ 0.42 = 1 C

0.42 mol of H/ 0.42 = 1 H

1.26 mol of Cl/0.42 = 3 Cl

The ratio of elements is 1:1:3

Therefore the empirical formula of the compound will be CHCl₃.

Learn more about empirical formula here:

brainly.com/question/20708102

#SPJ4

5 0
2 years ago
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