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densk [106]
3 years ago
12

A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the

ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (Use g = 9.8 m/s2.)
Physics
1 answer:
horsena [70]3 years ago
6 0

Answer:

7.0 m/s

Explanation: I just did it

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You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart
hichkok12 [17]

Answer:

v = 3.5 \times 10^5 m/s

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

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now we have

\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}

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so we will have

r = 3.46 \times 10^8 m

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-\frac{GM_e}{R_e} - \frac{GM_m}{d - (R_e + R_m)} + \frac{1}{2}v^2 = -\frac{GM_e}{r} - \frac{GM_m}{d - r}

-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5

v = 3.5 \times 10^5 m/s

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Answer:

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4) Newton

6 0
2 years ago
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