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sasho [114]
3 years ago
8

100 POINTS. Help Please.

Physics
2 answers:
Free_Kalibri [48]3 years ago
7 0

Answer:

The electrical force between two balloons is 67.5N.

Explanation:

There are two charged balloons, let's say a and b.

The charge on the balloon a = Q_a = 3.0 * 10^{-6}C

The charge on the balloon b = Q_b = 2.5 * 10^{-7}C

Both balloons are 1 cm apart; it means that the distance<em> r</em> between the balloon a and the balloon b is 0.01 m (since 1 cm = 0.01 m).

We need to find the electrical force between them. By using the Coulomb's law, the magnitude of the electrical force between both the balloon is given as follows:

F = \frac{kQ_aQ_b}{r^2} --- (A)

Where,

k = Coulomb's constant = \frac{1}{4\pi\epsilon_o} = 9 * 10^9 \frac{Nm^2}{C^2}

Plug all the values in the equation (A):

F = \frac{(9*10^9)(3.0*10^{-6})(2.5*10^{-7})}{(0.01)^2} \\F = 67.5 N

Hence, the electrical force between two balloons is 67.5N (three significant figures).

patriot [66]3 years ago
7 0

The magnitude of electrical force between them is about 68 Newton

<h3>Further explanation</h3>

Electric charge consists of two types i.e. positively electric charge and negatively electric charge.

\texttt{ }

There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :

\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }

<em>F = electric force (N)</em>

<em>k = electric constant (N m² / C²)</em>

<em>q = electric charge (C)</em>

<em>r = distance between charges (m)</em>

<em>The value of k in a vacuum = 9 x 10⁹ (N m² / C²)</em>

Let's tackle the problem now !

\texttt{ }

<u>Given:</u>

charge of balloon 1 = q₁ = 3.0 × 10⁻⁶ C

charge of balloon 2 = q₂ = 2.5 × 10⁻⁷ C

distance between balloon 1 and balloon 2 = R = 1 cm = 1 × 10⁻² m

<u>Unknown:</u>

electrical force between them = F = ?

<u>Solution:</u>

F = k \frac{q_1 q_2}{R^2}

F = 9 \times 10^9 \times \frac{ 3.0 \times 10^{-6} \times 2.5 \times 10^{-7} }{ ( 1 \times 10^{-2} )^2 }

F = 9 \times 10^9 \times \frac{ 7.5 \times 10^{-13} }{ 10^{-4} }

F = 9 \times 10^9 \times 7.5 \times 10^{-9}

F = 67.5 \texttt{ Newton}

F \approx 68 \texttt { Newton} →<em> ( 2 Significant Figures )</em>

\texttt{ }

<h3>Learn more</h3>
  • The three resistors : brainly.com/question/9503202
  • A series circuit : brainly.com/question/1518810
  • Compare and contrast a series and parallel circuit : brainly.com/question/539204

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Static Electricity

Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces

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