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ArbitrLikvidat [17]
3 years ago
6

It is known that a shark can travel at a speed of 17 m/s. How far can a shark go in 8 seconds?

Physics
1 answer:
o-na [289]3 years ago
6 0

Answer:136 m

Explanation:17*8

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What hanging mass will stretch a 3.0-m-long, 0.32 mm - diameter steel wire by 1.3 mm ? The Young's modulus of steel is 20×10^10
raketka [301]

Answer:

0.71 kg

Explanation:

L = length of the steel wire = 3.0 m

d = diameter of steel wire = 0.32 mm = 0.32 x 10⁻³ m

Area of cross-section of the steel wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (0.32 x 10⁻³)²

A = 8.04 x 10⁻⁸ m²

ΔL = change in length of the wire = 1.3 mm = 1.3 x 10⁻³ m

Y = Young's modulus of steel = 20 x 10¹⁰ Nm⁻²

m = mass hanging

F = weight of the mass hanging

Young's modulus of steel is given as

Y = \frac{FL}{A\Delta L}

20\times 10^{10} = \frac{F(3)}{(8.04\times 10^{-8})(1.3\times 10^{-3})}

F = 6.968 N

Weight of the hanging mass is given as

F = mg

6.968 = m (9.8)

m = 0.71 kg

7 0
4 years ago
Answer the assignment questions using the World Geology map in this lesson and/or the earth's lithospheric plates map in the ass
Advocard [28]
3 I think sorry if wrong
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3 years ago
A washing machine heats 10kg of water in each wash cycle. How much energy is saved by washing at 30'c instead of 50'c if the sta
Volgvan
The equation for this is very simple you add then you subtract then you get the answer then you divide then it all works out for you
6 0
4 years ago
The strength of the electric field 0.5 m from a 6 µc charge is n/c. (use k = 8.99 × 109 n•meters squared per coulomb squared and
diamong [38]

53....................................

Explanation:

6 0
2 years ago
Your aunt just turned 50 and now needs glasses to read.
alexira [117]

Answer:

(a) hypermetropia

(b) convex lens

(c) 133.33 cm

(d) - 21.05 cm

Explanation:

(a) As she is old age, so she is suffering from hypermetropia.

(b) It is the defect due to which a person is not able to see the nearby objects clearly, so it is cured by convex lens of suitable focal length.

(c) Power, P = + 0.75 D

Focal length is the reciprocal of power of lens.

f = 1/ P = 1/0.75

f = 133.33 cm

(d) v = -25 cm, f = 133.3 cm

use lens equation

\frac{1}{f}=\frac{1}{v}-\frac{1}{u}

\frac{1}{133.3}=\frac{-1}{25}-\frac{1}{u}

\frac{-1}{u}=\frac{133.33+25}{133.33\times25}

u = - 21.05 cm

8 0
3 years ago
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