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ArbitrLikvidat [17]
3 years ago
6

It is known that a shark can travel at a speed of 17 m/s. How far can a shark go in 8 seconds?

Physics
1 answer:
o-na [289]3 years ago
6 0

Answer:136 m

Explanation:17*8

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A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 64 feet per second. The d
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Answer:

a) t=6.37s

b) t=3.3333s

Explanation:

The knowable variables are the initial hight and initial velocity

s_{o}=80ft

v_{os}=64ft/s

The equation that describes the motion of the ball is:

s=80+64t-16t^{2}

If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.

0=80+64t-12t^{2}

a) Solving for t, we are going to have two answers

t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

a=-16

b=64

c=80

t=-1.045 s or t=6.378s

<em><u>Since time can not be negative the answer is t=6.378s </u></em>

b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too

First of all, we need to find the maximum hight and how much time does it take to reach it:

v_{y}=v_{o}+gt

at maximum point the velocity is 0

0=64-32.2t

Solving for t

t=1.9875 s

Now, we must know how much distance does it take to reach maximum point

s=0+64t-16t^{2} =64(1.9875)-12(1.9875)^{2} =80ft

So, the ball pass the top of the building on its way down at 160 ft

160=80+64t-16t^{2}

Solving for t

t=2s or t=3.333s

Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building

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If a small-diameter open glass tube is partially immersed in a vessel containing mercury, the surface of the mercury inside the
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The pressure outside (atmosphere) is greater than that inside the tube. This means that the mercury will be pushed up in the glass tube. This phenomenon is called the capillary rise. It shape would be like that of the outside of the umbrella. The answer is therefore letter D. 
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When an ice cube in a glass of water melts, the water level _____. A. remains the same B. rises C. falls
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A.  The water level Remains the same
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How does mechanical energy relate to the work an object can do
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If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     v=\sqrt{\frac{T}{(m/l)}}

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

(m/l)=\frac{10}{V^2}

Explanation:

From the question we are told that

Speed of a transverse wave given by

v=\sqrt{\frac{T}{(m/l)}}

Maximum Tension is T=10.0N

Generally making (m/l) subject from the equation mathematically we have

v=\sqrt{\frac{T}{(m/l)}}

v^2=\frac{T}{(m/l)}

(m/l)=\frac{T}{V^2}

(m/l)=\frac{10}{V^2}

Therefore the Linear mass in terms of Velocity is given by

(m/l)=\frac{10}{V^2}

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