2 even numbers....x and x + 2
x + x + 2 = 234
2x + 2 = 234
2x = 234 - 2
2x = 232
x = 232/2
x = 116 <===
x + 2 = 116 + 2 = 118 <==
F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235
Divide both sides by -5
Sqrt(x) = 3
We want to isolate x to solve for it. The opposite of a square root is a square, so square both sides.
x = 9
It can't be -9 because the square root of negative numbers are not real numbers.
Answer:
dy/dx = -b/a cot α
Step-by-step explanation:
x² / a² + y² / b² = 1
Take derivative with respect to x.
2x / a² + 2y / b² dy/dx = 0
2y / b² dy/dx = -2x / a²
dy/dx = -b²x / (a²y)
Substitute:
dy/dx = -b²a cos α / (a²b sin α)
dy/dx = -b cos α / (a sin α)
dy/dx = -b/a cot α
