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3 years ago

10

Comet is seen after a long period of time. Why?

1 answer:

lorasvet [3.4K]3 years ago

7 0

Answer:

Long-period comets have orbital periods longer than 200 years. ... Since it is the sublimation of these volatiles from the nucleus of the comet as it nears the Sun that gives rise to the coma and highly-visible tails, long-period comets have more material with which to put on a show.

Explanation:

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A toroidal solenoid with mean radius r and cross-sectional area A is wound uniformly with N1 turns. A second toroidal solenoid w

lilavasa [31]

Answer:

Mutual inductance, $M=2.28\times 10^{-5}\ H$

Explanation:

(a) A toroidal solenoid with mean radius r and cross-sectional area A is wound uniformly with N₁ turns. A second thyroidal solenoid with N₂ turns is wound uniformly on top of the first, so that the two solenoids have the same cross-sectional area and mean radius.

Mutual inductance is given by :

$M=\dfrac{\mu_oN_1N_2A}{2\pi r}$

(b) It is given that,

$N_1=550$

$N_2=290$

Radius, r = 10.6 cm = 0.106 m

Area of toroid, $A=0.76\ cm^2=7.6\times 10^{-5}\ m^2$

Mutual inductance, $M=\dfrac{4\pi \times 10^{-7}\times 550\times 290\times 7.6\times 10^{-5}}{2\pi \times 0.106}$

$M=0.0000228\ H$

or

$M=2.28\times 10^{-5}\ H$

So, the value of mutual inductance of the toroidal solenoid is $2.28\times 10^{-5}\ H$ . Hence, this is the required solution.

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3 years ago

Tara is an electrician. Which field of science does Tara need to know the most about in order to do her job?

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A law enforcement officer in an intergalactic "police car" turns on a red flashing light and sees it generate a flash every 1.2

butalik [34]

Answer:

The velocity of the police car relative to earth is $v_{rel} = 2.51\times 10^{8} m/s$

Given:

time for flash generation of the inter galactic police car, t = 1.2 s

time between flashes as measured from earth, t' = 2.2 s

Solution:

Utilising Einstein's equation for time dilation to calculate the velocity of the police car, the equation is given by:

$t' = \frac{t}{\sqrt {1 - \frac{v^{2}}{c^{2}}}}$ (1)

where, c = speed of light in vacuum = $c = 3\times 10^{8}$

re arranging eqn (1) for velocity, v:

$v_{rel} = c\times \sqrt {1 - (\frac{t}{t'})^{2}}$ (2)

Now, from eqn (2)

$v_{rel} = 3\times 10^{8}( \sqrt {1 - (\frac{1.2}{2.2})^{2}})$

$v_{rel} = 3\times 10^{8}\times 0.838$

$v_{rel} = 2.51\times 10^{8} m/s$

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3 years ago