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IrinaK [193]
3 years ago
9

A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5

m?
Physics
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

8.83m

Explanation:

Given parameters:

  Acceleration  = 7.8m/s²

   Initial velocity = 0m/s

  distance covered  = 5m

Unknown:

Final velocity  = ?

Solution:

The equation to solve this problem with is given as;

    V² = U² + 2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance

 Input the parameters and solve;

    V² = 0² + 2 x 7.8 x 5 = 78

    V = √78 = 8.83m

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Answer:

Solution

The atomic number of iodine (53) tells us that a neutral iodine atom contains 53 protons in its nucleus and 53 electrons outside its nucleus. Because the sum of the numbers of protons and neutrons equals the mass number, 127, the number of neutrons is 74 (127 − 53 = 74). Since the iodine is added as a 1− anion, the number of electrons is 54 [53 – (1–) = 54].

Check Your Learning

An ion of platinum has a mass number of 195 and contains 74 electrons. How many protons and neutrons does it contain, and what is its charge?

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3 years ago
A potter’s wheel moves from rest to an angular speed of 0.20 rev/s in 23.8 s. Assuming constant angular acceleration, what is it
ser-zykov [4K]

Answer:

0.053 rad/s^2

Explanation:

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