A red rubber ball rolls down a hill from rest with an acceleration of 7.8 m/s 2 . How fast is it moving after it has traveled 5
m?
1 answer:
Answer:
8.83m
Explanation:
Given parameters:
Acceleration = 7.8m/s²
Initial velocity = 0m/s
distance covered = 5m
Unknown:
Final velocity = ?
Solution:
The equation to solve this problem with is given as;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance
Input the parameters and solve;
V² = 0² + 2 x 7.8 x 5 = 78
V = √78 = 8.83m
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