Answer:
Vi = 4.38 m/s
Explanation:
Given
m = 1000 kg ;
y = 8m ;
T = 11000 N;
∑Fy = m*a
W - T = m * a
(1000kg * 9.8 m/s² ) - 11000N = 1000 kg * a
a = - 1.2 m/s²
Using the equation from parabolic motion
Vf ² = Vi² + 2*a*y
Solve to Vi
Vi = √ 2* 1.2m/s² * 8 m
Vi = √19.2 m²/s²
Vi = 4.38 m/s
Answer:
False
Explanation:
Something with high specific heat cooling down would take longer to heat up.
In both graphs, speed will be measured in meters/second.
In graph A, the object travelled a distance of 40 meters in 4 seconds
In graph B, the object is at rest for 5 seconds.
These are the correct answers
Answer:
Explanation:
given,
side of square loop = a = 2.10 cm
Resistance of the wire = 1.30×10⁻² Ω
Length of the loop = c = 1.10 cm
rate of increasing current = 130 A/s
Answer:
43.41 mm
Explanation:
Given:
thickness of sheet, t = 6 mm
Force exerted by punch, F = 45 KN
Average shearing stress, T = 55 MPa
From average shearing stress T = Force F / Area A
Hence area = force/stress =45000/ 55 =
From area = pi*diameter*thickness
diameter = area/(pi* thickness)
= 818.18/(3.142*6)
= 43.41 mm