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Sonbull [250]
3 years ago
10

A B C or D? With correct workings

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0

Answer:

A  the first choice

Step-by-step explanation:

Sin theta = opp/ hypotenuse

sin A = 12/16

12 must be opposite angle A and 16 must be the hypotenuse

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Read the ques
Dafna11 [192]

Answer:

0.25feet

Step-by-step explanation:

The equation is not well written. Let the equation of the height be modelled as;

h = -16d²+8d+4

The velocity of the ball is zero at its maximum height.

Velocity = change in displacement/time

v = dh/dd

Differentiate

v = -32d+8

Since dh/dd = v = 0

0 = -32d+8

Add 32d to both sides

0+32d = 8

32d = 8

Divide both sides by 32

32d/32 = 8/32

d = 1/4

d = 0.25feet

Hence the maximum height of the tennis ball is 0.25feet

Note that the modeled equation was assumed. You can apply the same calculation to any equation given

3 0
3 years ago
The diameter of the circle is 9.7 m . Calculate the length of its circumference. Round to the nearest tenth and remember to use
RSB [31]

Answer:

30.4m

Step-by-step explanation:

Diameter(D) = 2r (radius)

D = 9.7m

r = 9.7m / 2

= 4.85m

C = 2πr

= 2π × 4.85m

= 30.47344873982099m

rounding - Leave it as is if the digit in the tenth is 4 or lower

- round it up if it's 5 or higher.

~~ 30.4m

5 0
2 years ago
Why does the shape of the moon appear to change over the course of about a month? (2 points)
kirill [66]
B. The sun is lighting up different amounts of the moon
5 0
2 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
Which set of numbers is arranged from least to greatest?
Delvig [45]

Answer:

The correct answer is option B

6 0
3 years ago
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