<span>ultrasonic wave i think</span>
<h2>
Dimension for cheap enclose = 32.45 ft x 23.52 ft</h2>
Explanation:
Area of rectangular field, A = 830 ft²
Length = l
Width = w
So we have
l x w = 830

Fencing costs $2 per foot for two opposite sides, and $3 per foot for the other two sides.
Cost for fencing, C = 2 x 2 x w + 3 x 2 x l = 4 w + 6 l

For minimum cost we have derivative is zero

Dimension for cheap enclose = 32.45 ft x 23.52 ft
Answer:
A solid substance at its melting point has less energy than the same mass of the substance when it is a liquid at the same temperature. ... This heat energy allows the change of state to happen, and the temperature remains constant during the process.
Explanation:
Answer:
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So \frac{\lambda }{2}=20cm
2
λ
=20cm
\lambda =40cmλ=40cm
We have to find the speed of the wave in the string
Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec
So speed of the wave in the string will be 3.2 m/sec
Answer:
factor that bug maximum KE change is 0.52284
Explanation:
given data
vertical distance = 6.5 cm
ripples decrease to = 4.7 cm
solution
We apply here formula for the KE of particle that executes the simple harmonic motion that is express as
KE = (0.5) × m × A² × ω² .................1
and kinetic energy is directly proportional to square of the amplitude.
so
.............2

= 0.52284
so factor that bug maximum KE change is 0.52284