The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
The mass of the baseball, m = 0.15 kg
The speed at which it moves, v = 30 m/s
Time at which the baseball was in contact with the bat, t = 0.75 ms
t = 0.75/1000 s
t = 0.00075 s
The impulsive force is given by the formula:
Substitute m = 0.15 kg, v = 30, and t = 0.00075s into the formula above:
The magnitude of the average impulsive force imparted to the ball if it is in contact with the bat is 6000 N
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Radiation. That's perhaps the only way that energy gets from the Sun to the earth. The space between the two is a vacuum, so conduction is more or less out as is convection. There's no obvious sign of mirrors, so reflection seems to be out as well.
Answer:
V=f×λ
Where,
V is the velocity of the wave measure using m/s.
f is the frequency of the wave measured using Hz.
λ is the wavelength of the wave measured using m.
transform 46 cm in m = 0.46m and there u have it
Explanation:
Answer:
yo they deleted my answer. The answer is 0N
Explanation:
so when two forces pull on an object from opposite sides with the same force (in this case its 20N), then the object is in equilibrium at 0N.
So its clear that there is one person on the the opposite side.
SOOO generally<u>: (left or down) would be considered </u><u>negative</u><u> in an equation. And the other person (right or up) would be considered </u><u>positive</u><u>.</u> So if both forces are the same numbers on opposite sides then the answer is 0 (if you add both of them).
<em>0 is the number of equilibrium.</em>
OK, so the equation would be -20N + 20N and then badda bing badda boom viola, the answer: 0N
thanks for coming to my TED talk. I hope they don't delete this answer.
Answer:
1.11×10¹⁹ electrons
Explanation:
The formula for electric energy is given as,
E = QV ................. Equation 1
Where E = Electric Energy, Q = charge, V = Voltage.
Make Q the subject of the equation
Q = E/V............... Equation 2
Given: E = 8 W, V = 4.5 V.
Substitute into equation 2
Q = 8/4.5
Q = 1.778 C
using,
n = Q/e............ Equation 3
Where n = number of electron, e = Charge of one electron.
Given: e = 1.6×10⁻¹⁹ C
Substitute into equation 3
n = 1.778/1.6×10⁻¹⁹
n = 1.11×10¹⁹ electrons
