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Lady_Fox [76]
2 years ago
14

Using a refracting telescope, you observe the planet Mars when it is 1.99×1011 m from Earth. The diameter of the telescope's obj

ective lens is 0.977 m . What is the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you? Use 563 nm for the wavelength of light.
Physics
1 answer:
Rudik [331]2 years ago
5 0

The minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is  140km.

<h3>What is telescope?</h3>

Telescope is device through which we can see the distant objects very clearly as it seems like they are some meters away.

Distance of the Mars from the Earth D = 1.99 x 10¹¹ m

Diameter of telescope's objective lens d = 0.977 m

The wavelength of light λ in m, λ = 563nm = 563 x 10⁻⁹ m

The distance y or the minimum feature size  =1.22λD/d

Substitute the value, we get

y = 1.22 x 563 x 10⁻⁹ x 1.99 x 10¹¹ /0.977

y = 140 km (approximately)

Thus, the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is  140km.

Learn more about Telescope.

brainly.com/question/556195

#SPJ1

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a student drops an object from the top of a building which is 19.6 m high. How long does it take the object to fall to the groun
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Here's a formula that's simple and useful, and if you're really in
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This formula tells how far an object travels in how much time,
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For your student who dropped an object out of the window,

     Distance = 19.6 m
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Divide each side by 4.9 :       4  =           T²

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When an object is dropped in Earth gravity,
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Answer:

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Explanation:

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Allyson and Adrian have decided to connect their ankles with a bungee cord; one end is tied to each person's ankle. The cord is
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Complete question is;

Allyson and Adrian have decided to connect their ankles with a bungee cord; one end is tied to each person's ankle. The cord is 40 feet long, but can stretch up to 120 feet. They both start from the same location. Allyson moves 10 ft/sec and Adrian moves 9 ft/sec in the directions indicated. Adrian stops moving at time t = 5.5 sec, but Allyson keeps on moving 10 ft/sec in the indicated direction. (If a coordinate system is used, assume that the girls' starting position is located at

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The hypotenuse is the distance between Allyson and Adrian.

Thus, from pythagoras theorem, we can find the distance between them which is same as the length of the cord.

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(-49.5)² + 70² = D².

D² = 2450.25 + 4900

D = √7350.25

D = 85.734 ft

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