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Lady_Fox [76]
2 years ago
14

Using a refracting telescope, you observe the planet Mars when it is 1.99×1011 m from Earth. The diameter of the telescope's obj

ective lens is 0.977 m . What is the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you? Use 563 nm for the wavelength of light.
Physics
1 answer:
Rudik [331]2 years ago
5 0

The minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is  140km.

<h3>What is telescope?</h3>

Telescope is device through which we can see the distant objects very clearly as it seems like they are some meters away.

Distance of the Mars from the Earth D = 1.99 x 10¹¹ m

Diameter of telescope's objective lens d = 0.977 m

The wavelength of light λ in m, λ = 563nm = 563 x 10⁻⁹ m

The distance y or the minimum feature size  =1.22λD/d

Substitute the value, we get

y = 1.22 x 563 x 10⁻⁹ x 1.99 x 10¹¹ /0.977

y = 140 km (approximately)

Thus, the minimum feature size, in kilometers, on the surface of Mars that your telescope can resolve for you is  140km.

Learn more about Telescope.

brainly.com/question/556195

#SPJ1

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A passenger jet flies from one airport to another 1293 miles away in 2.1hours . Find average speed
JulsSmile [24]

The average speed is 615.7 mph (275.2 m/s)

Explanation:

The average speed of an object gives a measure of how fast an object is moving over a certain time interval. It is a scalar quantity, and it is calculated as follows

v=\frac{d}{t}

where

v is the average speed

d is the distance covered

t is the time interval

For the jet in this problem, we have:

d = 1293 mi is the distance covered

t = 2.1 h is the time interval

Therefore, the average  speed is:

v=\frac{1293}{2.1}=615.7 mph

We can also convert into SI units (m/s), keeping in mind that:

1 mi = 1609 m\\1 h = 3600 s

And so

v=615.7 \frac{mi}{h}\cdot \frac{1609 m/mi}{3600 s/h}=275.2 m/s

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6 0
3 years ago
A system in which only one particle can move has the potential energy shown in (figure 1). Suppose u1 = 60 j. What is the y-comp
marta [7]

The y-component of the force on the particle at the given position is 120 N.

<h3>Electric force on the particle</h3>

The electric force on the particle is determined by applying Coulomb's law and work-energy theorem as shown below;

Fd = W

Where;

  • F is the applied force
  • d is the distance
  • W is potential

F = W/d

F = 60/0.5

F = 120 N

Thus, the y-component of the force on the particle at the given position is 120 N.

Learn more about electric force here: brainly.com/question/20880591

3 0
2 years ago
Which of the following is a type of natural disaster that has impacted Florida?
Andrej [43]

Florida is aligned on the coast of the Gulf of Mexico. The Gulf is known for producing strong hurricanes due to its warm waters which hurricanes thrive on. Florida is hit by hurricanes pretty often.

6 0
3 years ago
Read 2 more answers
A small rock is thrown vertically upward with a speed of 17.0m/s from the edge of the roof of a 26.0m tall building. The rock do
Pachacha [2.7K]

Answer:

A) v = 28.3 m/s

B) t =  4.64 s

Explanation:

A)

  • Assuming no other forces acting on the rock, since the accelerarion due to gravity close to the surface to the Earth can be taken as constant, we can use one of the kinematic equations in order to get first the maximum height (over the roof level) that the ball reaches:

        v_{f}^{2} - v_{o}^{2} = 2* g* \Delta h  (1)

  • Taking into account that at this point, the speed of the rock is just zero, this means vf=0 in (1), so replacing by the givens and solving for Δh, we get:

       \Delta h = \frac{-v_{o} ^{2}}{2*g} = \frac{-(17.0m/s)^{2} }{2*(-9.8m/s2)} = 14.8 m (2)

  • So, we can use now the same equation, taking into account that the initial speed is zero (when it starts falling from the maximum height) and that the total vertical displacement is the distance between the roof level and the ground (26.0 m) plus the maximum height that we have just found in (2) , 14.8m:
  • Δh = 26.0 m + 14. 8 m = 40.8 m (3)
  • Replacing now in (1), we can solve for vf, as follows:

       v_{f} =\sqrt{2*g*\Delta h} = \sqrt{2*9.8m/s2*40.8m} = 28.3 m/s (4)

B)

  • In order to find the total elapsed from when the rock is thrown until it hits the street, we can divide this time in two parts:
  • 1) Time elapsed from the the rock is thrown, until it reaches to its maximum height, when vf =0
  • 2) Time elapsed from this point until it hits the street, with vo=0.
  • For the first part, we can simply use the definition of acceleration (g in this case), making vf =0, as follows:

       v_{f} = v_{o} + a*\Delta t = v_{o} - g*\Delta t = 0 (5)

  • Replacing by the givens in (5) and solving for Δt, we get:

       \Delta t = \frac{v_{o}}{g} = \frac{17.0m/s}{9.8m/s2} = 1.74 s (6)

  • For the second part, since we know the total vertical displacement from (3), and that vo = 0 since it starts to fall, we can use the kinematic equation for displacement, as follows:

       \Delta h = \frac{1}{2} * g * t^{2}  (7)

  • Replacing by the givens and solving for t in (7), we get:

       t_{fall} =\sqrt{\frac{2*\Delta h}{g}} = \sqrt{\frac{2*40.8m}{9.8m/s2} } = 2.9 s (8)

  • So, total time is just the sum of (6) and (8):
  • t = 2.9 s + 1.74 s = 4.64 s
5 0
2 years ago
A 110 kg ice hockey player skates at 3.0 m/s toward a railing at the edge of the ice and then stops himself by grasping the rail
disa [49]

Answer

given,

mass of ice hockey player = 110 Kg

initial speed of the skate = 3 m/s

final speed of the skate = 0 m/s

distance of the center of mass, m = 30 cm = 0.3 m

a) Change in kinetic energy

    \Delta KE = \dfrac{1}{2}mv_f^2 - \dfrac{1}{2}mv_i^2

    \Delta KE = \dfrac{1}{2}m(0)^2 - \dfrac{1}{2}\times 110 \times 3^2

    \Delta KE = - 495\ J

b) Average force must he exerted on the railing

     using work energy theorem

      W = Δ KE

      F .d  = -495

      F x 0.3  = -495

      F = -1650 N

the average force exerted on the railing is equal to 1650 N.

7 0
2 years ago
Read 2 more answers
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