When the specific heat capacity of the water is 4.18 J/g.°C so, we are going to use this formula to get the heat for cooling three phases changes from steam to liquid and from liquid to ice (solid) :
when Q = M*C*ΔT
Q is the heat in J
and M is the mass in gram = 1 mol H2O * 18 g/mol(molar mass) = 18 g
C is the specific heat J/g.°C
ΔT is the change in temperature
Q = Mw *[ ( Csteam * ΔTsteam)+(Cw*ΔTw) + (Cice * ΔT ice)]
= 18 g * [(2.01 * (155-100°C)) + (4.18 * (100-0°C)) + (2.09 * (0 - 55 °C))]
∴Q = 7444.8 J
and when we know that the heat of fusion for water = 334J/g
and heat of vaporization for water = 2260J/g
∴Q for the two phases changes = M * (2260+334)
= 18 * (2260+334)
= 46692 J
∴ Q total = 7444.8 + 46692 = 54136.8 J
Answer:
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Explanation:
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Answer:
Luster of aluminum is Silver-White.
Explanation:
Aluminium is a Silver-White metal which is extracted from the Bauxite ore which can be reddish brown, white, tan, grey-white and tan-yellow in color and have the minerals like Gibbsite, Boehmite and Diaspore which are the minerals of the aluminium.
The Bauxite is the rock from which the Bauxite ore is extracted which have the minerals of the aluminum.
The luster of a metal is the color and shine of it and its shiny appearance.
Aluminium is a light weight metal but have a moderate hardness which makes a wider use of it. Aluminium is used in many places where the weight of the material is kept light but its hardness can be increased by mixing some other metals in it making hard alloy with lighter weight.
It is used in transportation vehicles, buildings, and many other places like Air crafts as the weight should be kept controlled to give a perfect lift to the Air craft.
Explanation:
Initial Pressure = 24 lb in-2
Initial Temperature = –5 o C = 268 K (Converting to kelvin temperature)
Final Pressure = ?
Final Temperature = 35 o C = 308 K (Converting to kelvin temperature)
No Change in Volume.
From Gay Lusaac's law; pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.
P1T1 = P2T2
P2 = P1T1 / T2
P2 = 24 * 268 / 308 = 20.88 lb in-2
There would be a drop in pressure as the temperature increases. Appropriate measures should b taken by regularly gauging the pressure of the tire.
