Answer:169.6m/s
Explanation:
Wavelength=32cm=0.32m
Frequency=580Hz
Velocity=frequency x wavelength
Velocity=580x0.32
Velocity=169.6m/s
2,3,5 are correct just took the test
Answer:
wavelength = 0.968 m
frequency = 39.02 Hz
Explanation:
given data
mass = 0.0127 kg
force = 9.33 N
length = 1.93 m
to find out
wavelength and Frequency
solution
we know here linear density that is
linear density =
.........1
linear density =
linear density = 6.5803 ×
kg/m
so
wavelength will be here
wavelength =
..............2
here n = 4 for forth harmonic
wavelength = ![\frac{2*1.93}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B2%2A1.93%7D%7B4%7D)
wavelength = 0.968 m
and
frequency will be for 4th normal mode of vibration is
frequency =
..........3
frequency = ![\frac{4}{2*1.93} \sqrt{\frac{9.33}{6.5803*10^{-3}} }](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B2%2A1.93%7D%20%5Csqrt%7B%5Cfrac%7B9.33%7D%7B6.5803%2A10%5E%7B-3%7D%7D%20%7D)
frequency = 1.036269 × 37.654594
frequency = 39.02 Hz
A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,
- t= 0.45 seconds.
- V=2.22m/s
- VT=4.95 m/s
This is further explained below.
<h3>What is its speed when it hits the floor...?</h3>
Generally, the equation for motion is mathematically given as
S= ut + 0.5at²
Therefore
y = Voy t + 0.5gt^2
1 = 0.5x 98 x 6²
1=4.9t^2
![t=\sqrt{0.2041 }](https://tex.z-dn.net/?f=t%3D%5Csqrt%7B0.2041%20%7D)
t= 0.45 seconds.
b) Horizontal motions are uniform.
V=Horizontal displacement/time
V=1/0.45
V=2.22m/s
C)
Vx: 2.22 m/s At bottom,
Vy² = Voy² + 2as
Vy² = 2x95x1
Vy² = 19.6
Total velocity
![VT=\sqrt{( 2.22 m/)^2+19.6}](https://tex.z-dn.net/?f=VT%3D%5Csqrt%7B%28%202.22%20m%2F%29%5E2%2B19.6%7D)
VT=4.95 m/s
Read more about Arithmetic
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