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astra-53 [7]
1 year ago
8

A sample of carbon monoxide and oxygen gasses are

Chemistry
1 answer:
otez555 [7]1 year ago
3 0

Answer:

.0172 mole of CO2

Explanation:

PV = nR T      n = number of moles      V = .5 liter

                       R = gas constant = .082057 L atm/(k mole)

                           T needs to be in Kelvin =  C + 273.15

.868  * .5  = n * .082057 * ( 35 + 273.15)

 n = .0172 moles

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Answer:

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Explanation:

Using Boyle's law equation;

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P2 = final pressure (atm)

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According to the question below:

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