Question

A sample of carbon monoxide and oxygen gasses are

Answer 1

Answer:

.0172 mole of CO2

Explanation:

PV = nR T      n = number of moles      V = .5 liter

                       R = gas constant = .082057 L atm/(k mole)

                           T needs to be in Kelvin =  C + 273.15

.868  * .5  = n * .082057 * ( 35 + 273.15)

 n = .0172 moles