1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
patriot [66]
3 years ago
15

Consider a wet banked roadway, where there is a coefficient of static friction of 0.30 and a coefficient of kinetic friction of

0.25 between the tires and the roadway. The radius of the curve is R=50m.
Part A

If the banking angle is β=25∘, what is the maximum speed the automobile can have before sliding up the banking?

Part B

What is the minimum speed the automobile can have before sliding down the banking?
Physics
1 answer:
gulaghasi [49]3 years ago
6 0

Answer:

a) v = 20.9 m/s

b) v = 8.46 m/s

Explanation:

Given:-

- The coefficient of static friction is us = 0.30

- The coefficient of static friction is uk= 0.25

- The radius of the curve R = 50m

- The bank Angle β = 25

Find:-

a) If the banking angle is β=25∘, what is the maximum speed the automobile can have before sliding up the banking?  

b) What is the minimum speed the automobile can have before sliding down the banking?

Solution:-

- We will investigate the sliding-up case first. Develop a FBD as given in (attachment).

- Use Newton's second law of motion vertical to slope of bank where the car is in equilibrium:

                       Sum ( F_n ) = 0

                       N*cos(β) - m*g - Ff*sin(β) = 0

Where,            Frictional Force Ff = us*N

                      N (cos(β) - us*sin(β)) = mg   ... Eq 1

- Use Newton's second law of motion horizontal to slope of bank where the car is accelerating:

                       Sum ( F_h ) = m*a

                       Ff*cos(β) + Nsin(β) = m*v^2 / R

                       N (us*cos (β) + sin (β) ) = m*v^2 / R  .... Eq 2

- Divide the two equations:

                    v^2 / gR = [ us*cos (β) + sin (β) ] / [ cos (β) - us*sin (β) ]

                    v^2 = [ 0.25*cos (25) + sin (25) ]*9.81*50 / [ cos (25) - 0.25*sin (25) ]

                    v = 20.9 m/s

- For the slip down case. We have, friction force Ff reversed hence us = -us. Then the v can be given as:

                    v^2 / gR = [ -us*cos (β) + sin (β) ] / [ cos (β) + us*sin (β) ]

                    v^2 = [ -0.25*cos (25) + sin (25) ]*9.81*50 / [ cos (25) + 0.25*sin (25) ]

                    v = 8.46 m/s

You might be interested in
A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed on 10 m/s. If air
fiasKO [112]

The distance of the rock from the base of the cliff is C) 20 m

Explanation:

The motion of the rock in this problem is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion to find the time of flight of the rock (the time it takes to reach the ground). We can do it by using the suvat equation:

s=u_y t+\frac{1}{2}at^2

where, taking downward as positive direction,

s = 20 m is the vertical displacement of the rock

u_y=0 is the initial vertical velocity

t is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

Now we can analzye the horizontal motion: the rock moves horizontally with a constant velocity of

v_x = 10 m/s

Therefore, the horizontal distance covered after a time t is

d=v_x t

and substituting t = 2.02 s, we find the final distance of the rock from the base of the cliff:

d=(10)(2.02)=20 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

6 0
3 years ago
What is the direction of the centripetal force when applied to an object?
mihalych1998 [28]
For an object moving in a path that's a circle or a part of one,
the centripetal force acts in the direction toward the center of
the circle.  That direction is perpendicular to the way the object
is moving.
3 0
3 years ago
Read 2 more answers
The Hawaiian hot spot sits below the Pacific plate. As the plate moves over the hot spot, a chain of volcanoes is formed. The Ea
Viktor [21]

Answer:

3.2048179721\times 10^{-9}\ m/s

Explanation:

Assuming that the pacific plate moved 178 km in 1.76 million years.

s = Distance = 178 km

t = Time taken = 1.76 million years

Speed is given by

v=\dfrac{s}{t}\\\Rightarrow v=\dfrac{178000}{1.76\times 10^6\times 365.25\times 24\times 3600}\\\Rightarrow v=3.2048179721\times 10^{-9}\ m/s

The speed of the plate is 3.2048179721\times 10^{-9}\ m/s

6 0
3 years ago
Hey any physicist or engineer around. am giving brainliest to anyone who will answer this question.
Oduvanchick [21]

Answer:

N = 167 Newtons

R = 727 Newtons

Explanation:

i) For static equilibrium, moments about any convenient point must sum to zero.

A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.

ii) I will <em>ASSUME </em>the two moment arms are 0.05m and 0.15 m

CCW moments about the fulcrum are

190 N(0.2 m) + 280 N(0.05 m) = 52 N•m

CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m

For static equilibrium, these must be equal

27 + 0.15N = 52

       0.15N = 25

              N = 166.6666666...

Sum moments about N to zero

(Same as saying CW and CCW moments must balance)

190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0

R = 726.6666666...

We could verify this by summing vertical forces to zero.

R - 190 - 280 - 166.666666 - 90 = 0

R = 726.6666666...

8 0
3 years ago
Which variable is represented by the following symbol? µ
devlian [24]

Answer:

c. Friction coefficient

is the correct answer

8 0
2 years ago
Other questions:
  • A 360.0 $g$ block is dropped onto a vertical spring with a spring constant k = 254.0 $N/m$. The block becomes attached to the sp
    8·1 answer
  • What can parents do if they find a mistake in the student records?      A. They can’t do anything B. Make a correction themselve
    11·2 answers
  • Which piece of evidence contradicts the steady state theory?
    14·2 answers
  • A football is kicked from ground level with an initial velocity of 23.6 m/s at angle of 57.5° above the horizontal. How long, in
    12·1 answer
  • If a light wave is reflected with a 27° angle of reflection, what was the angle of incidence of which it was transmitted?
    10·1 answer
  • Now moving horizontally, the skier crosses a patch of soft snow, where the coefficient of friction is μk = 0.160. If the patch i
    10·1 answer
  • Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. If you were to hit a basketb
    9·2 answers
  • Define the term energy density of a body under strain​
    7·1 answer
  • Help me plz.<br>Show workings​
    15·2 answers
  • What is kinematics?<br>explain!!~​<br><br>thankyou ~
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!